Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 2:
a: =>x/4=1/8
hay x=1/2
b: \(\Leftrightarrow\dfrac{x}{-5}=\dfrac{11}{6}\)
hay x=-55/6
c: \(\Leftrightarrow\dfrac{-3.5}{x}=\dfrac{4.25}{8}\)
hay x=-112/17
a) \(\frac{3x-2}{1\frac{2}{5}}=\frac{2\frac{3}{7}}{2\frac{3}{5}}\Rightarrow3x-2=1.\frac{2}{5}.\frac{2\frac{3}{7}}{2\frac{3}{5}}=\frac{7}{5}.\frac{17}{7}.\frac{5}{13}\)
\(3x-2=\frac{17}{13}\Rightarrow3x=2+\frac{17}{13}=\frac{43}{13}\Rightarrow x=\frac{43}{39}.\)
b) \(\frac{x}{0,16}=\frac{9}{x}\Rightarrow x^2=9.0,16=1,44\Rightarrow x=\pm1,2\)
\(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)
\(\Rightarrow\left(x-1\right)\left(x+4\right)=\left(x-2\right)\left(x+3\right)\)
\(\Leftrightarrow x^2+4x-x-4=x^2+3x-2x-6\)
\(\Leftrightarrow x^2+4x-x-4-x^2-3x+2x+6=0\)
\(\Leftrightarrow2x+2=0\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-1\)VẬY X=-1 LÀ NGHIỆM CỦA PHƯƠNG TRÌNH \(\frac{x-1}{x-2}=\frac{x+3}{x+4}\)
P/s : Vì bạn lớp 7 nên mình giải chi tiết nha!
Có \(\frac{x-1}{x+2}=\frac{x-2}{x+3}\Leftrightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Leftrightarrow x\left(x+3\right)-1\left(x+3\right)=x\left(x-2\right)+2\left(x-2\right)\)
\(\Leftrightarrow x^2+3x-x-3=x^2-2x+2x-4\)
\(\Leftrightarrow x^2+\left(3x-x\right)-3=x^2+\left(2x-2x\right)-4\)
\(\Leftrightarrow x^2+2x-3=x^2-4\Leftrightarrow x^2-x^2+2x=3-4=-1\)
\(=\left(x^2-x^2\right)+2x=-1\Leftrightarrow2x=1\Leftrightarrow x=1\div2=\frac{1}{2}\)
\(\frac{-12}{x}=\frac{4}{13}\)
\(\Rightarrow4x=13.\left(-12\right)=-156\)
\(\Rightarrow x=-156:4=-39\)
\(\frac{-15}{72}=\frac{125}{-3y}\)
\(\Rightarrow\frac{-15}{72}=\frac{-3000}{72y}\)
\(\Rightarrow-15y=-3000\)
\(\Rightarrow y=-3000:-15=200\)
\(\frac{49}{21}=\frac{-14z}{-7}\)
\(\Rightarrow\frac{49}{21}=\frac{42z}{21}\)
\(\Rightarrow49=42z\)
\(\Rightarrow z=\frac{49}{42}\)
=> (72 - x) . 9 = (x - 40) . 7
=> 648 - 9x = 7x - 280
=> (-280) - 648 = -9x - 7x
-928 = -16x
=> x = 58