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Ta có 1/2*3=1/2-1/3;
1/3*4=1/3-1/4
......................(tương tự với các số khác)
1/149*150=1/149-1/150
=>A=1/2-1/3+1/3-1/4+1/4-1/5+...-1/149+1/149-1/150=1/2-1/150
A=75/150-1/150=74/150=37/75
Vậy A= 37/75
a) 3+\(\left|x+7\right|\) =4
\(\left|x+7\right|\) =4-3
\(\left|x+7\right|\) =1
\(\Rightarrow\)x+7=1 hoặc x+7 =-1
✽ x+7=1 \(\Rightarrow\)x=-6
✽x+7 =-1\(\Rightarrow\)x=-8
Vậy x=-6, x=-8
Lời giải:
1. $(x+2)-2=0$
$x+2=2$
$x=0$
2.
$(x+3)+1=7$
$x+3=7-1=6$
$x=6-3=3$
3.
$(3x-4)+4=12$
$3x-4+4=12$
$3x=12$
$x=12:3=4$
4.
$(5x+4)-1=13$
$5x+4=13+1=14$
$5x=14-4=10$
$x=10:5=2$
5.
$(4x-8)-3=5$
$4x-8=5+3=8$
$4x=8+8=16$
$x=16:4=4$
6.
$3+(x-5)=7$
$x-5=7-3=4$
$x=4+5=9$
7.
$8-(2x-4)=2$
$2x-4=8-2=6$
$2x=6+4=10$
$x=10:2=5$
8.
$7+(5x+2)=14$
$5x+2=14-7=7$
$5x=7-2=5$
$x=5:5=1$
9.
$5-(3x-11)=1$
$3x-11=5-1=4$
$3x=11+4=15$
$x=15:3=5$
10.
$16-(8x+2)=6$
$8x+2=16-6=10$
$8x=10-2=8$
$x=8:8=1$
Bài 1 :
a) \(...=45\left(56+44\right)-500=45.100-500=4500-500=4000\)
b) \(...=3^2.6-6^{18}+1=45+1-6^{18}=46-6^{18}\)
c) \(...=756\left(66+48-14\right)=756.100=75600\)
d) \(...=8.15-\left(149-7^2\right)=120-\left(149-49\right)=120-100=20\)
Bài 2 :
a) \(x-21=46\Rightarrow x=21+46\Rightarrow x=87\)
b) \(2^x.4=128\Rightarrow2^x=32\Rightarrow2^x=2^5\Rightarrow x=5\)
c) \(3x+27=162\Rightarrow3x=162-27\Rightarrow3x=135\Rightarrow x=45\)
d) \(4x-8=4^{2023}.4^{2021}\)
\(\Rightarrow4x-8=4^{2023+2021}\)
\(\Rightarrow4x-8=4^{4044}\)
\(\Rightarrow4x=4^{4044}+8\)
\(\Rightarrow x=\left(4^{4044}+8\right):4\)
\(\Rightarrow x=4^{4043}+2\)
1/ \(-12;-7;-1;0;4;10;\left|-18\right|\)
2/ \(-13;-5;0;+3;\left|+4\right|;12;\left|-15\right|\)
3/ \(\left|-26\right|;19;-\left(-12\right);0;-4;-\left|35\right|\)
4/ \(-\left(-73\right);\left|+7\right|;4;\left|-1\right|;0;+\left(-5\right);-\left(+22\right)\)
Bài 20:
*Tăng dần
1/ -12; -7; -1; 0; +4; 10; |-18|
2/ -13; -5; 0; +3; |+4|; 12; |-15|
*Giảm dần
3/ |-26|; +19; -(-12); 0; -4; -|-35|
4/ -(-73); | +7|; 4; |-1|; 0; +(-5); -(+22)
Chúc bạn học tốt !!!
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
Ta có: \(A=\frac{3}{1\cdot5}+\frac{3}{5\cdot4}+\frac{3}{4\cdot11}+...+\frac{3}{73\cdot149}+\frac{3}{149\cdot76}\)
\(\Rightarrow A=\frac{1}{2}\cdot\left(\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+...+\frac{3}{146\cdot149}+\frac{3}{149\cdot152}\right)\)
\(\Rightarrow A=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{146}-\frac{1}{149}+\frac{1}{149}-\frac{1}{152}\right)\)
\(\Rightarrow A=\frac{1}{2}\cdot\left(\frac{1}{2}-\frac{1}{152}\right)=\frac{1}{2}\cdot\left(\frac{76}{152}-\frac{1}{152}\right)=\frac{1}{2}\cdot\frac{75}{152}=\frac{75}{304}\)
Đáp án là D
Ta có: