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a) 5 . 42 – 18 : 32 = 5 . 16 - 18 : 9 = 80 - 2 = 78;
b) 33 . 18 – 33 . 12 = 27 . 18 - 27 . 12 = 486 - 324 = 162;
Lưu ý. Có thể áp dụng tính chất phân phối của phép nhân đối với phép cộng:
33 . 18 – 33 . 12 = 33 (18 - 12) = 27 . 6 = 162;
c) 39 . 213 + 87 . 39 = 39 . (213 + 87) = 39 . 300 = 11700;
d) 80 – [130 – (12 – 4)2] = 80 - (130 - 64) = 80 - 66 = 14.
4 . 24 . 5 ^ 2 - ( 3 ^ 3 . 18 + 3 ^ 3 . 12 )
= 4 . 24 . 25 - ( 9 . 18 + 9 . 12 )
= ( 4 . 25 ) . 24 - 9 . ( 18 + 12 )
= 100 . 24 - 9 . 30
= 2400 - 270
= 2130
\(4.24.5^2-\left(3^3.18+3^3.12\right)\)
=\(24.100-3^3\left(18+12\right)\)
=\(24000-270=23730\)
A= (-4/5+4/3)+(-5/4+14/5)-7/3
= 8/15+31/20-7/3
= 25/12-7/3
= -1/4
B= 8/3.2/5.3/8.10.19/92
= 16/15.3/8.10.19/92
= 2/5.10.19/92
= 4.19/92
= 19/23
C= \(\frac{-5}{7}\).\(\frac{2}{11}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+1\(\frac{5}{7}\)
=\(\frac{-5}{7}\).\(\frac{2}{11}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+\(\frac{12}{7}\)
= \(\frac{-10}{77}\)+\(\frac{-5}{7}\).\(\frac{9}{14}\)+\(\frac{12}{7}\)
= \(\frac{-10}{77}\)+\(\frac{-45}{98}\)+\(\frac{12}{7}\)
= \(\frac{-635}{1078}\)+\(\frac{12}{7}\)
= \(\frac{1213}{1078}\)
=52.22.11+22.52.89-9.103
=52.22(11+89)-9.103
=(5.2)2.100-9.103
=102.102_9.103
=103(10-9)
=103=1000
2^2 .74 . 5^2 + 5^2 . 26 . 4 -1000
= 2 .74 .25 + 25 . 26 .4 -1000
= 7400 + 2600 -1000
=9000
Áp dụng tc: \(\frac{1}{n}.\left(1+2+3+...+n\right)=\frac{1}{n}.\frac{n.\left(n+1\right)}{2}=\frac{n+1}{2}\)
=> H = \(\frac{1}{2}.2+\frac{1}{2}.3+\frac{1}{2}.4+...+\frac{1}{2}.85=\frac{1}{2}.\left(2+3+4+...+85\right)\)
= \(\frac{1}{2}.\left(1+2+3+4+...+85-1\right)=\frac{1}{2}.\left(\frac{85.86}{2}-1\right)=\frac{1}{2}.3654=1827\)
b: \(\Leftrightarrow x-10\left(\dfrac{2}{11\cdot13}+\dfrac{2}{13\cdot15}+...+\dfrac{2}{53\cdot55}\right)=\dfrac{3}{11}\)
\(\Leftrightarrow x-10\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{53}-\dfrac{1}{55}\right)=\dfrac{3}{11}\)
\(\Leftrightarrow x-10\cdot\dfrac{4}{55}=\dfrac{3}{11}\)
=>x=3/11+20/55=3/11+4/11=7/11
c: \(\Leftrightarrow\left(\dfrac{x-1}{99}-1\right)+\left(\dfrac{x-2}{98}-1\right)+\left(\dfrac{x-5}{95}-1\right)=\dfrac{1}{99}+\dfrac{1}{98}+\dfrac{1}{95}\)
\(\Leftrightarrow x-100=1\)
hay x=101
4 x 24 x 52 - (33 x 18 + 33 x 12 )
= 4 x 24 x 25 - ( 27 x 18 + 27 x 12 )
= 100 x 24 - [ 27 x ( 28 + 12 )]
= 2400 - ( 27 x 30 )
= 2400 - 810
= 1590
4.24.52 - ( 33.18 + 33.12)
= 4.24.25 - 33( 18 + 12 )
= 100.24 - 33.30
=2400 - 27.30
= 2400 - 810 = 1590