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a) \(x\cdot\frac{13}{20}+x:2=\frac{4}{7}\)
\(x\cdot\frac{13}{20}+x\cdot\frac{1}{2}=\frac{4}{7}\)
\(x\cdot\left(\frac{13}{20}+\frac{1}{2}\right)=\frac{4}{7}\)
\(x\cdot\frac{23}{20}=\frac{4}{7}\)
\(x=\frac{4}{7}:\frac{23}{20}\)
b) \(x:1+x:\frac{1}{2}+x:\frac{125}{1000}=6\)
\(x\cdot\frac{1}{2}+x\cdot2+x\cdot8=6\)
\(x\cdot\left(\frac{1}{2}+2+8\right)=6\)
\(x\cdot\frac{21}{2}=6\)
\(x=6:\frac{21}{2}\)
\(x=\frac{6}{7}\)
\(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(\Leftrightarrow x+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(\Leftrightarrow x\left(1+\frac{1}{3}\times\frac{9}{2}+\frac{7}{2}\right)=252\)
\(\Leftrightarrow x\left(\frac{6}{6}+\frac{9}{6}+\frac{21}{6}\right)=252\)
\(\Leftrightarrow x\times\frac{36}{6}=252\)
\(\Leftrightarrow x\times6=252\)
\(\Leftrightarrow x=252\div6\)
\(\Leftrightarrow x=43\)
\(\frac{x+9}{13-x}=\frac{6}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+9=6\\13-x=5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-3\\x=8\end{cases}}\)
\(\frac{120-x}{30}=3\frac{1}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{7}{2}\)
\(\Rightarrow\frac{120-x}{30}=\frac{105}{30}\)
\(\Rightarrow120-x=105\)
\(\Rightarrow x=120-105\)
\(\Rightarrow x=15\)
a,
\(x+\frac{7}{15}=1\frac{1}{20}\)
\(x+\frac{7}{15}=\frac{21}{20}\)
\(x=\frac{21}{20}-\frac{7}{15}=\frac{63}{60}-\frac{28}{60}\)
\(x=\frac{35}{60}=\frac{7}{12}\)
b,
\(\left[3\frac{1}{2}-x\right]\cdot1\frac{1}{4}=\frac{15}{16}\)
\(\left[\frac{7}{2}-x\right]\cdot\frac{5}{4}=\frac{15}{16}\)
\(\frac{7}{2}-x=\frac{15}{16}:\frac{5}{4}=\frac{3}{4}\)
\(\frac{7}{2}-x=\frac{3}{4}\Rightarrow x=\frac{7}{2}-\frac{3}{4}\)
\(x=\frac{11}{4}\)
c,
\(1\frac{1}{5}x+\frac{2}{3}x=\frac{56}{125}\Leftrightarrow\frac{6}{5}x+\frac{2}{3}x=\frac{56}{125}\)
\(\frac{28}{15}x=\frac{56}{125}\Rightarrow x=\frac{6}{25}\)
d,
\(60\%x+0,4x+x:3=2\)
\(\frac{3}{5}x+\frac{2}{5}x+\frac{1}{3}x=2\)
\(\frac{4}{3}x=2\Rightarrow x=\frac{3}{2}\)
Nguyễn Anh Thiện
a)
x + \(\frac{7}{15}\) = \(1\frac{1}{20}\)
X + \(\frac{7}{15}=\frac{21}{20}\)
X \(=\frac{21}{20}-\frac{7}{15}\)
X \(=\frac{63}{60}-\frac{28}{60}=\frac{35}{60}=\frac{7}{12}\)
^^ Học tốt !
Ta có : \(\frac{1}{4}+\frac{1}{3}:\frac{1}{x}=\frac{11}{12}\)
\(\Rightarrow\frac{1}{3}:\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)
\(\frac{1}{3}:\frac{1}{x}=\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}:\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}\times\frac{3}{2}\)
\(\frac{1}{x}=\frac{1}{2}\)
=> x = 2
a) \(\frac{x\div3-16}{2}+21=38\)
\(\frac{x\div3-16}{2}=38+21\)
\(\frac{x\div3-16}{2}=59\)
\(x\div3-16=59.2\)
\(x\div3-16=118\)
\(x\div3=118+16\)
\(x\div3=134\)
\(x=134.3\)
\(x=402\)
b) \(\frac{1}{4}+\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}\)
\(\frac{1}{3}\div\frac{1}{x}=\frac{11}{12}-\frac{1}{4}\)
\(\frac{1}{3}\div\frac{1}{x}=\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{3}\div\frac{2}{3}\)
\(\frac{1}{x}=\frac{1}{2}\)
Vậy x = ....
a, \(x-\frac{1}{3}=\frac{3}{4}\)
\(x=\frac{3}{4}+\frac{1}{3}\)
\(x=\frac{9}{13}+\frac{4}{12}=\frac{13}{12}\)
a. \(x=\frac{3}{4}+\frac{1}{3}\)
\(x=\frac{10}{12}\)
b. \(x+\frac{5}{2}=\frac{15}{4}\)
\(x=\frac{15}{4}-\frac{5}{2}\)
\(x=\frac{5}{4}\)
c. \(x:\frac{1}{4}=\frac{37}{2}\)
\(x=\frac{37}{2}\)x \(\frac{1}{4}\)
\(x=\frac{37}{8}\)
d. \(x=\frac{2}{9}:\frac{2}{3}\)
\(x=\frac{2}{9}\)x \(\frac{3}{2}\)
\(x=\frac{1}{3}\)
\(631-\frac{2}{3}:x=125\)
\(\frac{2}{3}:x=631-125\)
\(\frac{2}{3}:x=506\)
\(x=\frac{2}{3}:506\)
\(x=\frac{1}{759}\)
631-2/3:x=125
=>2/3:x=506
=>x=1/759