Question

[Lan nhi Duong nguyễn]

Tìm x thuộc N để (2n+3):(n+1)

Answer 1

[Sakuraba Laura]

\(2n+3⋮n+1\Leftrightarrow2\left(n+1\right)+1⋮n+1\)

\(\Rightarrow1⋮n+1\)(vì 2(n+1) chia hết cho n+1)

\(\Rightarrow n+1\inƯ\left(1\right)=\left\{1\right\}\)

\(\Rightarrow n+1=1\)

\(\Rightarrow n=0\)

Vậy \(n=0\)