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a) \(2^{x-1}+2^{x+1}+2^{x+2}=104\)
=> \(2^{x-1}+2^x\cdot2+2^x\cdot2^2=104\)
=> \(2^x:2+2^x\cdot\left(2+2^2\right)=104\)
=> \(2^x\cdot\frac{1}{2}+2^x\cdot6=104\)
=> \(2^x\cdot\left(\frac{1}{2}+6\right)=104\Rightarrow2^x=104:\left(\frac{1}{2}+6\right)=104:\frac{13}{2}=16\)
=> \(x=4\)
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=480\)
\(\Rightarrow2^x.\left(1+2+2^2+2^3\right)=480\)
\(\Rightarrow2^x.15=480\)
\(\Rightarrow2^x=480:15\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)
Chúc bạn học tốt !!!!
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Leftrightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=480\)
\(\Leftrightarrow2^x\left(1+2+2^2+2^3\right)=480\)
\(\Leftrightarrow2^x.15=480\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Leftrightarrow x=5\)
2x + 2x + 1 + 2x + 2 + 2x + 3 = 480
15 . 2x = 480
2x = 480 : 15
2x = 32
2x = 25
=> x = 5
2x + 2x+1 + 2x+2 + 2x+3 = 480
=> 2x(1+2+22+23) = 480
=> 2x . 15 = 480
=> 2x = 32
=> 2x = 25
=> x = 5
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x+2^x.2+2^x.4+2^x.8=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
Vậy \(x=5\)
a,x3=1
x=1
b,(x-5)2=16
(x-5)2=42
x-5=4
x=9
c,3x=92
3x=34
x=4
d,2x.27:25=1024
2x+7-5=210
x+7-5=10
x=8
2^x + 2^x+1 + 2^x+2 + 2^x+3 =480
2^x.(1+2+2^2+2^3)=480
2^x.15=480
2^x=32
=> x=5