\(|3x-\dfrac{3}{2}|=3\)

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29 tháng 11 2023

|3x-3/2|=3

3x-3/2=3 hoặc 3x-3/2=-3

TH1: 3x-3/2=3

3x=3+3/2

3x=9/2

x=9/2:3

x=3/2

TH2: 3x-3/2=-3

3x=-3+3/2

3x=-3/2

x=-3/2:3

x=-1/2

Vậy x=3/2 hoặc x=-1/2

30 tháng 11 2023

|3x|=3+3/2 , |3x|=9/2 ,|x|=9/2 : 3, |x|=3/2,[x=3/2

                                                                 [x=(-3/2)

a: \(\Leftrightarrow\dfrac{3}{4}:\dfrac{22}{9}-\left|3x-\dfrac{8}{3}\right|=\dfrac{3}{4}\)

\(\Leftrightarrow\left|3x-\dfrac{8}{3}\right|=\dfrac{3}{4}\cdot\dfrac{9}{22}-\dfrac{3}{4}=\dfrac{3}{4}\cdot\dfrac{-13}{22}=\dfrac{-39}{88}\)(loại)

b: \(\Leftrightarrow\left[{}\begin{matrix}3x-2=x-\dfrac{1}{3}\\3x-2=\dfrac{1}{3}-x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{5}{3}\\4x=\dfrac{7}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=\dfrac{7}{12}\end{matrix}\right.\)

27 tháng 11 2022

b: =>(3x-1)(3x+1)(2x+3)=0

hay \(x\in\left\{\dfrac{1}{3};-\dfrac{1}{3};-\dfrac{3}{2}\right\}\)

c: \(\Leftrightarrow\left|2x-\dfrac{1}{3}\right|=\dfrac{5}{6}+\dfrac{3}{4}=\dfrac{19}{12}\)

=>2x-1/3=19/12 hoặc 2x-1/3=-19/12

=>2x=23/12 hoặc 2x=-15/12=-5/4

=>x=23/24 hoặc x=-5/8

d: \(\Leftrightarrow-\dfrac{5}{6}\cdot x+\dfrac{3}{4}=-\dfrac{3}{4}\)

=>-5/6x=-3/2

=>x=3/2:5/6=3/2*6/5=18/10=9/5

e: =>2/5x-1/2=3/4 hoặc 2/5x-1/2=-3/4

=>2/5x=5/4 hoặc 2/5x=-1/4

=>x=5/4:2/5=25/8 hoặc x=-1/4:2/5=-1/4*5/2=-5/8

f: =>14x-21=9x+6

=>5x=27

=>x=27/5

h: =>(2/3)^2x+1=(2/3)^27

=>2x+1=27

=>x=13

i: =>5^3x*(2+5^2)=3375

=>5^3x=125

=>3x=3

=>x=1

30 tháng 8 2019

1) -2/3

1: \(\Leftrightarrow3x+4=2\)

=>3x=-2

=>x=-2/3

2: \(\Leftrightarrow7x-7=6x-30\)

=>x=-23

3: =>\(5x-5=3x+9\)

=>2x=14

=>x=7

4: =>9x+15=14x+7

=>-5x=-8

=>x=8/5

28 tháng 6 2017

a) |2x - 1| = 3x + 2

<=> \(\left[{}\begin{matrix}2x-1=3x+2\\2x-1=-3x-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-3=x\\5x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-\dfrac{1}{5}\end{matrix}\right.\)

b) \(2x-\dfrac{4}{3}-1\dfrac{2}{3}=1\)

\(2x-\dfrac{4}{3}-\dfrac{5}{3}=1\)

\(2x-\dfrac{9}{3}=1\)

\(2x-3=1\)

<=> x = 4 : 2 = 2

c) \(\left|3x-\dfrac{1}{4}\right|=x-1\dfrac{3}{4}\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{1}{4}=x-1\dfrac{3}{4}\\3x-\dfrac{1}{4}=-x+1\dfrac{3}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{7}{4}+\dfrac{1}{4}\\4x=\dfrac{7}{4}+\dfrac{1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{3}{2}\\4x=2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{3}{4}\\x=\dfrac{1}{2}\end{matrix}\right.\)

28 tháng 6 2017

a, \(\dfrac{5}{6}-\left|2-x\right|=\dfrac{1}{3}\Rightarrow\dfrac{5}{6}-\dfrac{1}{3}=\left|2-x\right|\)

<=> \(\dfrac{1}{2}=\left|2-x\right|\) \(\Leftrightarrow\left[{}\begin{matrix}2-x=\dfrac{1}{2}\\2-x=\dfrac{-1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)

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Mấy câu sau tương tự thôi

21 tháng 1 2018

a)\(\dfrac{3}{2}hay\dfrac{-3}{2}\)

b)\(\dfrac{13}{20}hay\dfrac{-13}{20}\)

c)\(\dfrac{11}{6}hay\dfrac{-11}{6}\)

d)\(\dfrac{4}{3}hay\dfrac{-4}{3}\)

e)\(\dfrac{1}{5}hay\dfrac{-1}{5}\)

Đây là câu trả lời của mình

Hay có nghĩa là hoặc

10 tháng 9 2017

a/ \(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{-1}{15}+3x=\dfrac{3}{4}\)

\(\Leftrightarrow3x=\dfrac{49}{60}\)

\(\Leftrightarrow x=\dfrac{49}{180}\)

Vậy....

b/ \(\dfrac{3}{2}-1+4x=\dfrac{2}{3}-7x\)

\(\Leftrightarrow\dfrac{1}{2}+4x=\dfrac{2}{3}-7x\)

\(\Leftrightarrow4x+7x=\dfrac{2}{3}-\dfrac{1}{2}\)

\(\Leftrightarrow11x=\dfrac{1}{6}\)

\(\Leftrightarrow x=\dfrac{1}{66}\)

Vậy....

c/ \(2\left(\dfrac{3}{4}-5x\right)=\dfrac{4}{5}-3x\)

\(\Leftrightarrow\dfrac{3}{2}-10x=\dfrac{4}{5}-3x\)

\(\Leftrightarrow-10x+3x=\dfrac{4}{5}-\dfrac{3}{2}\)

\(\Leftrightarrow-7x=-\dfrac{7}{10}\)

\(\Leftrightarrow x=-\dfrac{1}{10}\)

Vậy .....

10 tháng 9 2017

d/ \(4\left(\dfrac{1}{2}-x\right)-5\left(x-\dfrac{3}{10}\right)=\dfrac{7}{4}\)

\(\Leftrightarrow2-4x-5x-\dfrac{3}{2}=\dfrac{7}{4}\)

\(\Leftrightarrow2+\left(-4x\right)+\left(-5x\right)+\left(\dfrac{-3}{2}\right)=\dfrac{7}{4}\)

\(\Leftrightarrow-9x+\dfrac{1}{2}=\dfrac{7}{4}\)

\(\Leftrightarrow-9x=\dfrac{5}{4}\)

\(\Leftrightarrow x=-\dfrac{5}{36}\)

18 tháng 6 2018

Bài 1:

1)

\(\dfrac{3x+2}{4}\) = \(\dfrac{5x-3}{3}\)

<=> 3(3x + 2) = 4(5x - 3)

<=> 9x + 6 = 20x - 12

<=> 6 +12 = 20x - 9x

<=> 11x = 18

<=> x = \(\dfrac{18}{11}\)

Vậy: x = \(\dfrac{18}{11}\)

2)

\(\dfrac{x-1}{3x+2}\)= \(\dfrac{1}{5}\)

<=> 5(x - 1) = 3x + 2

<=> 5x - 5 = 3x + 2

<=> 5x - 3x = 2 +5

<=> 2x = 7

<=> x = \(\dfrac{7}{2}\)

Vậy : x = \(\dfrac{7}{2}\)

18 tháng 6 2018

Bài 1 :

1) Ta có :

\(\dfrac{3x+2}{4}=\dfrac{5x-3}{3}\\ \Leftrightarrow4\cdot\left(5x-3\right)=3\cdot\left(3x+2\right)\\ \Leftrightarrow20x-12=9x+6\\ \Leftrightarrow20x-18=9x\\ \Leftrightarrow20x-9x=18\\ \Leftrightarrow11x=18\\ \Leftrightarrow x=\dfrac{18}{11}\\ Vậy.,...\)

2) Ta có :

\(\dfrac{x-1}{3x+2}=\dfrac{1}{5}\Leftrightarrow5\cdot\left(x-1\right)=3x+2\\ \Leftrightarrow5x-5=3x+2\\ \Leftrightarrow5x-3x-5=2\\ \Leftrightarrow2x-5=2\\ \Leftrightarrow2x=7\\ \Leftrightarrow x=\dfrac{7}{2}\)

Vậy ....

Bài 2 ;

1) Áp dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x+y}{3+4}=\dfrac{21}{7}=3\\ \Rightarrow\left\{{}\begin{matrix}x=3\cdot3=9\\y=3\cdot4=12\end{matrix}\right.\\ Vậy...\)

2) Ta có : \(3x=5y\Leftrightarrow\dfrac{x}{5}=\dfrac{y}{3}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{x-y}{5-3}=\dfrac{-16}{2}=-8\\ \Rightarrow\left\{{}\begin{matrix}x=-8\cdot5=-40\\y=-8\cdot3=-24\end{matrix}\right.\\ Vậy....\)

3) Ta có : \(4x=7y\Leftrightarrow\dfrac{x}{7}=\dfrac{y}{4}=\dfrac{x^2}{7^2}=\dfrac{y^2}{4^2}=\dfrac{x\cdot y}{7\cdot4}\\ \Leftrightarrow\dfrac{x}{7}=\dfrac{y}{4}=\dfrac{112}{28}=4\\ \Rightarrow\left\{{}\begin{matrix}x=4\cdot7=28\\y=4\cdot4=16\end{matrix}\right.\\ Vậy...\)

a: \(\dfrac{2.75}{x}=\dfrac{0.4}{1.5}=\dfrac{4}{15}\)

\(\Leftrightarrow x=\dfrac{11}{4}\cdot\dfrac{15}{4}=\dfrac{165}{16}\)

b: \(3\dfrac{1}{2}:\left(2x-3\right)=\dfrac{-3}{4}:0.2\)

\(\Leftrightarrow\dfrac{7}{2}:\left(2x-3\right)=\dfrac{-3}{4}:\dfrac{1}{5}=\dfrac{-15}{4}\)

\(\Leftrightarrow2x-3=\dfrac{7}{2}:\dfrac{-15}{4}=\dfrac{-7}{2}\cdot\dfrac{4}{15}=\dfrac{-28}{30}=\dfrac{-14}{15}\)

=>2x=-14/15+3=45/45-14/15=31/45

=>x=31/90

c: \(\dfrac{3x+2}{27}=\dfrac{3}{3x+2}\)

\(\Leftrightarrow\left(3x+2\right)^2=81\)

=>3x+2=9 hoặc 3x+2=-9

=>3x=7 hoặc 3x=-11

=>x=7/3 hoặc x=-11/3

d: \(\dfrac{5-x}{4}=\dfrac{2x+3}{2}\)

=>10-2x=8x+12

=>-10x=2

hay x=-1/5

3 tháng 7 2017

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(3x=\dfrac{1}{3}-\dfrac{2}{5}-\dfrac{3}{4}\)

\(3x=-\dfrac{49}{60}\)

\(x=-\dfrac{49}{60}:3\)

\(x=-\dfrac{49}{180}\)

3 tháng 7 2017

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(\Rightarrow\dfrac{2}{5}+3x=\dfrac{1}{3}-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{2}{5}+3x=-\dfrac{5}{12}\)

\(\Rightarrow3x=-\dfrac{49}{60}\)

\(\Rightarrow x=-\dfrac{49}{180}\)

15 tháng 10 2018

\(1,\dfrac{2x+4}{7}=\dfrac{4x-2}{15}=\dfrac{2.\left(2x+4\right)}{2.7}=\dfrac{4x+8}{14}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\dfrac{2x+4}{7}=\dfrac{4x-2}{15}==\dfrac{4x+8}{14}=\dfrac{\left(4x+8\right)-\left(4x-2\right)}{14-15}=\dfrac{10}{-1}=-10\)

\(\Rightarrow\dfrac{2x+4}{7}=-10\)

\(\Rightarrow2x+4=-10.7=-70\)

\(\Rightarrow2x=-70+4=-66\)

\(\Rightarrow x=-66:2=-33\)

Vậy \(x=-33\)

\(2,\dfrac{2x+3}{5}=\dfrac{7x-3}{15}=\dfrac{7.\left(2x+3\right)}{7.5}=\dfrac{2.\left(7x-3\right)}{2.15}=\dfrac{14x+21}{35}=\dfrac{14x-6}{30}\)

Áp dụng tính chất của dãy tỉ số bằng nhau ta có :

\(\dfrac{2x+3}{5}=\dfrac{14x+21}{35}=\dfrac{14x-6}{30}=\dfrac{\left(14x+21\right)-\left(14x-6\right)}{35-30}=\dfrac{29}{5}\)

\(\Rightarrow\dfrac{2x+3}{5}=\dfrac{29}{5}\)

\(\Rightarrow2x+3=29\)

\(\Rightarrow2x=29-3=26\)

\(\Rightarrow x=26:2=13\)

\(3,\dfrac{11x-2}{7x+5}=\dfrac{11}{8}\)

\(\Rightarrow\dfrac{11x-2}{11}=\dfrac{7x+5}{8}=\dfrac{7.\left(11x-2\right)}{7.11}=\dfrac{11.\left(7x+5\right)}{8.11}=\dfrac{77x-14}{77}=\dfrac{77x+55}{88}=\dfrac{\left(77x+55\right)-\left(77x-14\right)}{88-77}=\dfrac{69}{11}\)

\(\Rightarrow\dfrac{11x-2}{11}=\dfrac{69}{11}\)

\(\Rightarrow11x-2=69\)

\(\Rightarrow11x=69+2=71\)

\(\Rightarrow x=\dfrac{71}{11}\)