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a) [192 - (45 : 15) ^4 ] = [192 - (3)^4]
= [192 - 81]
= 111
a) [192 - ( 45 : 15)4 ]
= 192 - 34
= 192 - 81
= 110
b) [ (192 - 45 : 15) : 3)2 ]
= [ (192 - 45 : 15) : 3)2 ]
= [ (192 - 3) : 3)2
= (189 : 3)2
= 632
= 3969
a) 32-6.(8-23)+18
= 32 - 6 . (8 - 8) +18
=32 - 0 +18
= 50
b) (3.5-9)3.(1+2.3)2+42
= (15-9 )3. (1+6)2 + 4 2
= 63 . 7 2 + 42
= 216 x 49 + 16
= 10584 + 16
=10600
c) 9234:[3.3.(1+83)]
= 9234 : [ 3.3.93]
= 9234 : [ 3.3 . 729]
= 9234 :6561
= 1,407407407
d) 76- {2.[2.52-(31-2.3)]}+3.25
= 76 - { 2. [ 2.52 - ( 31 - 6)]} + 3.25
= 76 - { 2 . [ 2. 52 - 25 ]} + 3 .25
= 76 - { 2 . [2. 25 - 25]} + 3.25
= 76 - { 2.[ 50 - 25 ]} + 3.25
= 76 - { 2. 25} + 3 . 25
= 76 - 50 + 3. 25
= 76 - 50 + 75
= 101
a) \(A=1+3+3^2+.....+3^{10}⋮4\)
\(=\left(1+3\right)+\left(3^2+3^3\right)+.......+\left(3^9+3^{10}\right)\)
\(=\left(1+3\right)+\left(3^2\cdot1+3^2\cdot3\right)+.....+\left(3^9\cdot1+3^9\cdot3\right)\)
\(=\left(1+3\right)+3^2\left(1+3\right)+....+3^9\left(1+3\right)\)
\(=4\cdot1+3^2\cdot4+.......+3^9\cdot4\)
\(=4\cdot\left(1+3^2+.....+3^9\right)⋮4\)
Do đó A \(⋮\) 4
b) \(B=16^5+2^{15}⋮33\)
Ta có \(B=16^5+2^{15}\)
\(=\left(2^4\right)^5+2^{15}\)
\(=2^{20}+2^{15}\)
\(=2^{15}\cdot2^5+2^{15}\cdot1\)
\(=2^{15}\cdot\left(2^5+1\right)\)
\(=2^5\cdot\left(32+1\right)\)
\(=2^{15}\cdot33⋮33\)
Do đó \(B⋮33\)
Bài 1 :
a, Ta có : \(\left(-123\right)+\left|-13\right|+\left(-7\right)\)
= \(\left(-123\right)+13+\left(-7\right)=\left(-117\right)\)
b, Ta có : \(\left|-10\right|+\left|45\right|+\left(-\left|-455\right|\right)+\left|-750\right|\)
= \(10+45-455+750=350\)
c, Ta có : \(-\left|-33\right|+\left(-15\right)+20-\left|45-40\right|-57\)
= \(\left(-33\right)+\left(-15\right)+20-5-57=-90\)
\(\left[192-\left(45:15\right)^4\right]:3\)
\(=\left(192-3^4\right):3\)
\(=192:3-3^4:3\)
\(=64-3^3\)
\(=64-27\)
\(=37\)
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