Question

[ko có tên]

Làm tính chia ( 8x^2y^5 - 2x^2 y^2 +3xy) : (-2xy)

Answer 1

[Kiều Vũ Linh]

\(\left(8x^2y^5-2x^2y^2=3xy\right):\left(-2xy\right)\)
\(=\left[8x^2y^5:\left(-2xy\right)\right]+\left(2x^2:2xy\right)+\left[3xy:\left(-2xy\right)\right]\)

\(=-4xy^4+xy-\dfrac{3}{2}\)