Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) x2 + x - 12 = x2 - 3x + 4x - 12 = x(x - 3) + 4(x - 3) = (x - 3)(x + 4)
b) x2 - x - 12 = x2 + 3x - 4x - 12 = x(x + 3) - 4(x + 3) = (x + 3)(x - 4)
c) x2 - 9x + 20 = x2 - 4x - 5x + 20 = x(x - 4) - 5(x - 4) = (x - 4)(x - 5)
d) x2 + 9x + 20 = x2 + 4x + 5x + 20 = x(x + 4) + 5(x + 4) = (x + 4)(x + 5)
a,x^2+x-12=x^2-3x+4x-12
=x(x-3)+4(x-3)
=(x-3)*(x+4)
b) x2 - x - 12 = x2 + 3x - 4x - 12 = x(x + 3) - 4(x + 3) = (x + 3)(x - 4)
a,(x+y)(2a-4)
b,(x+y)(a-b)
c,a(b+a)(x-5)
d,2a(a+2)(x+y)
**** cho mk nha
a) x2 + x - 20 = x2 - 4x + 5x - 20 = x(x - 4) + 5(x - 4) = (x - 4)(x + 5)
b) x2 - x - 20 = x2 + 4x - 5x - 20 = x(x + 4) - 5(x + 4) = (x + 4)(x - 5)
c) 2x2 - 3x - 2 = 2x2 - 4x + x - 2 = 2x(x - 2) + (x - 2) = (x - 2)(2x + 1)
d) 3x2 + x - 2 = 3x2 + 3x - 2x - 2 = 3x(x + 1) - 2(x + 1) = (x + 1)(3x - 2)
a. \(=6x^2-4x-9x+6=2x\left(3x-2\right)-3\left(3x-2\right)=\left(3x-2\right)\left(2x-3\right)\)
b. \(=6x^2+4x+9x+6=2x\left(3x+2\right)+3\left(3x+2\right)=\left(3x+2\right)\left(2x+3\right)\)
a ) \(x^2-5x+6\)
\(=\left(x^2-2x\right)-\left(3x-6\right)\)
\(=x\left(x-2\right)-3\left(x-2\right)\)
\(=\left(x-2\right)\left(x-3\right)\)
b )\(x^2+5x+6\)
\(=\left(x^2+2x\right)+\left(3x+6\right)\)
\(=x\left(x+2\right)+3\left(x+2\right)\)
\(=\left(x+2\right)\left(x+3\right)\)
a.x^2 - 5x + 6
=x2-2x-3x+6
=x(x-2)-3(x-2)
=(x-3)(x-2)
b.x^2 + 5x + 6
=x2+3x+2x+6
=x(x+3)+2(x+3)
=(x+2)(x+3)
c ) \(x^2-7x+12\)
\(=\left(x^2-3x\right)-\left(4x-12\right)\)
\(=x\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-4\right)\left(x-3\right)\)
d ) \(x^2+7x+12\)
\(=\left(x^2+3x\right)+\left(4x+12\right)\)
\(=x\left(x+3\right)+4\left(x+3\right)\)
\(=\left(x+4\right)\left(x+3\right)\)
\(a\left(x-1\right)+b\left(1-x\right)=a\left(x-1\right)-b\left(x-1\right)=\left(x-1\right)\left(a-b\right)\)
a) ( x + 1) + b ( 1 - x )
= ( x + 1 ) - b( x- 1 )
= ( 1 - b )( x- 1 )
****