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1 tháng 11 2020

a) 49( y - 4 )2 - 9( y + 2 )2

= 72( y - 4 )2 - 32( y + 2 )2

= ( 7y - 28 )2 - ( 3y + 6 )2

= ( 7y - 28 - 3y - 6 )( 7y - 28 + 3y + 6 )

= ( 4y - 34 )( 10y - 22 )

= 2( 2y - 17 ).2( 5y - 11 )

= 4( 2y - 17 )( 5y - 11 )

b) 3x2 - 5x - 2 = 3x2 - 6x + x - 2 = 3x( x - 2 ) + ( x - 2 ) = ( x - 2 )( 3x + 1 )

c) x2 - 7xy + 10y2 = x2 - 2xy - 5xy + 10y2 = x( x - 2y ) - 5y( x - 2y ) = ( x - 2y )( x - 5y )

d) 3x2 - 10xy + 3y2 = 3x2 - 9xy - xy + 3y2 = 3x( x - 3y ) - y( x - 3y ) = ( x - 3y )( 3x - y )

29 tháng 1 2020

a) \(x^2-10x+9\)

\(=x^2-9x-x+9\)

\(=x\left(x-9\right)-\left(x-9\right)\)

\(=\left(x-1\right)\left(x-9\right)\)

29 tháng 1 2020

b) \(3x^2-10xy+3y^2\)

\(=3x^2-9xy-xy+3y^2\)

\(=3x\left(x-3y\right)-y\left(x-3y\right)\)

\(=\left(3x-y\right)\left(x-3y\right)\)

20 tháng 8 2021

a) x4 + 6x2y + 9y2 - 1 

= (x2 + 3y)2 - 1

= (x2 + 3y + 1)(x2 + 3y - 1) 

b) 2x2 + 3x - 5 

 = 2x2 - 2x + 5x - 5 

= 2x(x - 1) + 5(x - 1) 

= (2x + 5)(x - 1) 

c) x2 - 7xy + 10y2 

 = x2 - 2xy - 5xy + 10y2 

 = x(x - 2y) - 5y(x - 2y) 

= (x - 5y)(x - 2y) 

20 tháng 8 2021

a,  \(x^4+6x^2y+9y^2-1\)

\(=\left(x^2+3y\right)^2-1\)

\(=\left(x^2+3y-1\right)\left(x^2+3y+1\right)\)

b,  \(2x^2+3x-5\)

\(=2x^2-2x+5x-5\)

\(=2x\left(x-1\right)+5\left(x-1\right)=\left(x-1\right)\left(2x+5\right)\)

c,   \(x^2-7xy+10y^2\)

\(=x^2-4xy+4y^2-3xy+6y^2\)

\(=\left(x-2y\right)^2-3y\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x-5y\right)\)

9 tháng 7 2016

1)\(x^4+2x^3+x^2\)

=\(\left(x^4+x^3\right)+\left(x^3+x^2\right)\)đật nhân tử chung ra

=\(x^2\left(x+1\right)^2\)

2) pt => \(\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

=\(\left(x+y\right)^3-\left(x+y\right)\)

=\(\left(x+y\right)\left(\left(x+y\right)^2+1\right)\)

3)chia tất cả cho 5 pt => \(x^2-2xy+y^2-4x^2\)

=\(\left(x+y\right)^2-4z^2\)

=\(\left(x+y+2z\right)\left(x+y-2z\right)\)

4)pt => \(2\left(x-y\right)-\left(x^2-2xy+y^2\right)\)

=\(2\left(x-y\right)-\left(x-y\right)^2\)

=\(\left(x-y\right)\left(2-x+y\right)\)

k chi nha

10 tháng 7 2018

a ) 

\(5x^2-10xy+5y^2-20z^2\)

\(=5\left(x^2-2xy+y^2-4z^2\right)\)

\(=5\left[\left(x-y\right)^2-4z^2\right]\)

b ) 

\(-5x^2-16x-3\)

\(=-5x^2-15x-x-3\)

\(=-5x\left(x+3\right)-\left(x+3\right)\)

\(=\left(-5x-1\right)\left(x+3\right)\)

c ) 

\(x^2-5x+5y-y^2\)

\(=\left(x^2-y^2\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left[\left(x+y\right)-5\right]\)

d ) 

\(3x^2-6xy+3y^2-12z^2\)

\(=3\left(x^2-2xy+y^2-4z^2\right)\)

\(=3\left[\left(x-y\right)^2-4z^2\right]\)

10 tháng 7 2018

P/s :  Mình bổ sung : 

a ) 

\(=5\left(x-y-2z\right)\left(x-y+2z\right)\)

d ) 

\(=3\left(x-y-2z\right)\left(x-y+2z\right)\)

14 tháng 8 2019

a/ \(12x^2+5x-12y^2+12y-10xy-3.\)

\(=12x^2+9x-4x-12y^2+6y+6y-18xy+8xy-3.\)

\(=\left(12x^2-18xy+9x\right)-\left(4x-6y+3\right)+\left(8xy-12y^2+6y\right)\)

\(=3x\left(4x-6y+3\right)-\left(4x-6y+3\right)+2y\left(4x-6y+3\right)\)

\(=\left(4x-6y+3\right)\left(3x-1+2y\right)\)

2/ \(2x^2+y^2+3x-2y-3xy+1\)

\(=\left(y^2-2y+1\right)+\left(3x-3xy\right)+2x^2\)

\(=\left(y-1\right)^2+3x\left(1-y\right)+2x^2\)

\(=\left(y-1\right)^2-3x\left(y-1\right)+2x^2\)

14 tháng 7 2019

a) \(4x^2-4x+1=\left(2x-1\right)^2\)

14 tháng 7 2019

\(3x\left(x-5\right)-x\left(4+3x\right)=43\)

\(\Leftrightarrow3x^2-15x-4x-3x^2=43\)

\(\Leftrightarrow-19x=43\)

\(\Leftrightarrow x=\frac{-43}{19}\)

11 tháng 7 2016

1/ \(3x^2+6x+3-3y^2=3x^2+3x+3x+3-3y^2\)

\(=3\left(x^2+2x+1-y^2\right)\)

\(=3\left[\left(x^2+2x+1\right)-y^2\right]\)

\(=3\left[\left(x+1\right)^2-y^2\right]\)

\(=3\left(x+1-y\right)\left(x+1+y\right)\)

2/ \(25-x^2-y^2+2xy=5^2-\left(x^2+y^2-2xy\right)\)

\(=5^2-\left(x-y\right)^2\)

\(=\left[5-\left(x-y\right)\right]\left(5+x+y\right)\)

\(=\left(5-x+y\right)\left(5+x+y\right)\)

3/ \(3x-3y-x^2+2xy-y^2=3\left(x-y\right)-\left(x^2-2xy+y^2\right)\)

\(=3\left(x-y\right)-\left(x-y\right)^2\)

\(=\left(x-y\right)\left[3-\left(x-y\right)\right]\)

\(=\left(x-y\right)\left(3-x+y\right)\)

22 tháng 7 2018

a) \(^{x^4-y^4}\)

\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)

\(=\left[\left(x-y\right).\left(x+y\right)\right].\left(x^2-y^2\right)\)

\(=\left(x-y\right).\left(x+y\right).\left(x^2-y^2\right)\)

c) \(\left(3x-2y\right)^2-\left(2x-3y\right)^2\)

\(=\left[\left(3x-2y\right)+\left(2x-3y\right)\right].\left[\left(3x-2y\right)-\left(2x-3y\right)\right]\)

\(=\left(3x-2y+2x-3y\right)\left(3x-2y-2x+3y\right)\)

b) \(x^2-3y^2\)

\(=\left(x-3y\right)\left(x+3y\right)\)

d) \(9\left(x-y\right)^2-4\left(x+y\right)^2\)

\(=9\left(x-y\right)^2+4\left(x-y\right)^2\)

\(=\left(x-y\right).\left(9+4\right)\)

\(=\left(x-y\right).13\)

\(=13\left(x-y\right)\)

f) \(x^3+27\)

\(=x^3+3^3\)

\(=\left(x+3\right)\left(x^2-x.3+3^2\right)\)

h) \(125x^3-1\)

\(=\left(5x\right)^3-1^3\)

\(=\left(5x-1\right)\left(5x^2+5x.1+1^2\right)\)

\(=\left(5x-1\right)\left(5x^2+5x+1\right)\)

22 tháng 7 2018

\(a,x^4-y^4=\left(x^2+y^2\right)\left(x^2-y^2\right)=\left(x^2+y^2\right)\left(x+y\right)\left(x-y\right)\)

\(b,x^2-3y^2=\left(x+\sqrt{3}y\right)\left(x-\sqrt{3}y\right)\)

cn lại tg tự nha bn