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Câu 1:
a: \(=8^8\left(8^2-8-1\right)=8^8\cdot55⋮55\)
b: \(=3^{28}-3^{27}-3^{26}=3^{26}\left(3^2-3-1\right)=3^{26}\cdot5=3^{24}\cdot45⋮45\)
c: \(=7^4\left(7^2+7-1\right)=7^4\cdot55⋮11\)
1. A - B = 40+ 3/8 + 7/82 + 5/83 + 32/85 - (24/82 + 40+ 5/82 + 40/84 + 5/84 )
= 40.85/85 + 3.84/85 + 7.83/85 + 5.82/85 + 32/85 - 24.83/85 - 40.85/85 - 5.83/85 - 40.8/85 - 5.8/85
= 40.85/85 + 24.83/85 + 7.83/85 + 5.82/85 + 32/85 - 24.83/85 - 40.85/85 - 5.83/85 - 40.8/85 - 5.8/85
= 7.83/85 + 5.82/85 + 32/85 - 5.83/85 - 40.8/85 - 5.8/85
= 7.83/85 + 5.82/85 -8/85 - 5.83/85 - 40.8/85
= 2.83/85 + 5.82/85 - 40.8/85 - 8/85
= 2.83/85 + 40.8/85 - 40.8/85 - 8/85
= 2.83/85 - 8/85 > 0
Vay A > B
( 2^7*5^9 - 2^7*2^8) : ( 2^9: 2^7)
= [ 2^7*( 5^9-5^8) : 2^2
= [ 2^7* 5] : 4
= 160
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(9^4-3^8\right)\left(10^6-7^5\right)\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-7^5\right)\left[\left(3^2\right)^4-3^8\right]\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-5^7\right)\left(3^8-3^8\right)\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-5^7\right).0\)
\(A=0\)
\(9!-8!-7!.8^2=9!-8!-8!.8=8!\left(9-1-8\right)=8!.0=0\)