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1. a) 3^2 .2^2 .2^4 = 3^2. 2^(2+4)=3^2. 2^6
b) 10^2. 10^3.10^5= 10^(2+3+5)= 10^10
c) x.x^5=x^(1+5)=x^6
d) a^3 .a^2 ,a^5= a^(3+2+5)= a^10
2. a) 2^3 và 3^2 . Ta có: 2^3 = 8, 3^2=9 => 2^3 < 3^2
b) 2^4 và 4^2. Ta có: 2^4= 16, 4^2=16 => 2^4 = 4^2
c) 2^5 và 5^2. Ta có: 2^5= 32, 5^2=25 => 2^5 > 5^2
d) 2^100 và 100. => 2^100 > 100
3. a) 3^8:3^4= 3^(8-4)=3^4
b) 10^8:10^2=10^(8-6)=10^2
c) a^6: a (a#0) = a^(6-1)=a^5
\(1)A=a\frac{1}{3}+a\frac{1}{4}-a\frac{1}{6}=a\left(\frac{1}{3}+\frac{1}{4}-\frac{1}{6}\right)=a\frac{5}{12}\)
Thay \(a=-\frac{3}{5}\) vào A,ta đc:
\(A=-\frac{3}{5}.\frac{5}{12}=-\frac{1}{4}\)
\(2)B=b\frac{5}{6}+b\frac{3}{4}-b\frac{1}{2}=b\left(\frac{5}{6}+\frac{3}{4}-\frac{1}{2}\right)=b\frac{13}{12}\)
Thay \(b=\frac{12}{13}\) vào B, ta đc: \(B=b\frac{13}{12}=\frac{12}{13}.\frac{13}{12}=1\)
a
\(5\frac{4}{7}:x+=13\)
\(\frac{39}{7}:x=13\)
\(x=\frac{39}{7}:13\)
\(x=\frac{3}{7}\)
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=\frac{7}{4}=1\frac{3}{4}\)
a)(25.5-52.2):(5.2)-3
= (25.5-25.2):10-3
= 25.(5-2):10-3
= 25.3:10-3
=75:10-3=7,5-3=4,5
b)(6.52 -137).2-23.(7+3)(Sai đề)
c)23-53 :52 +12.22
= 8-125:25+12.4
= 8-5+12.4=8-5+48=3+48=51
d)2.[(95+52:5):22 +180] -22.102
= 2.[(95+25:5):4+180]-4.100
= 2.[(95+5):4+180]-400
= 2.(100:4+180)-400
= 2. (25+180)-400
= 2. 205-400
= 410-400=10
e)27.22+54:53.24-3.25
= 128+625:125.24-3.32
= 128+5.24-96
= 128+120-96
= 248-96=152
f)2.[(7-33 :32):22+99]-100
=2.[(7-27:9):4+99]-100
=2.[(7-3):4+99]-100
=2. (4:4+99)-100
=2. (1+99)-100
=2. 100-100
= 200-100
=100
Chúc Bạn Học Tốt ^_^
\(A\frac{27^4.8^{17}}{9^6.32^3}=\frac{\left(3^3\right)^4.\left(2^3\right)^{17}}{\left(3^2\right)^6.\left(2^5\right)^3}=\frac{3^{12}.2^{51}}{3^{12}.2^{15}}=\frac{3^{12}.2^{15}.2^{36}}{3^{12}.2^{15}}=2^{36}\)
\(B=\frac{72^3.54^3:8^3}{108^5:4^5}=\frac{\left(72.54:8\right)^3}{\left(108:4\right)^5}=\frac{486^3}{27^5}=\frac{\left(3^5.2\right)^3}{\left(3^3\right)^5}=\frac{3^{15}.2^3}{3^{15}}=2^3=8\)
Bài 2
A = 2 +22 + 23 + 24 + ....+ 2100
A = ( 2+22 ) + (23 + 24 ) + ....+ (299 + 2100 )
A = 2(1+2 ) + 23 (1+2 ) + ...+ 299(1+2)
A = 2.3 + 23.3 + ....+ 299 .3
A = 3(2+23 + ...+ 299 )
=> A \(⋮\) 3 ( đpcm )
Bài 3
a, 2.3x = 312 .34 + 20 .274
2.3x = 312 . 34 + 20 . (33 ) 4
2.3x = 312 .34 + 20 .312
2.3x = 312(34+20 )
2.3x = 312 . 54
2.3x = 312 . 27 .2
2.3x = 312 . 33 .2
2.3x = 315 .2
=> x=15
b , (2x +1 ) 2 + 3.(22 + 1 ) = 22 .10
(2x +1 ) 2 + 3.(4+1 ) = 4.10
(2x +1 ) 2 + 3.5 = 40
(2x +1 ) 2 + 15 = 40
(2x +1 ) 2 = 40-15
(2x +1 ) 2 = 25
(2x +1 ) 2 = 52
=> 2x + 1 = 5
2x = 5-1
2x = 4
2x = 22
=> x=2
a) \(2^3=2.2.2=8\)
\(2^4=2.8=16\)
\(2^5=2.16=32\)
\(2^6=2.32=64\)
\(2^7=2.64=128\)
\(2^8=2.128=256\)
\(2^9=2.256=512\)
\(2^{10}=2.512=1024\)
b) \(4^2=4.4=16\)
\(4^3=16.4=64\)
\(4^4=64.4=256\)
Còn lại tương tự
a) \(2^{3+4+5+6+7+8+9+10}=2^{52}\)
b) \(3^{14}\)\(=4782969\)
c) \(4^9\)\(=262144\)
d) \(5^9\)\(=1953125\)
e) \(6^9\)\(=10077696\)
K mk nha, mk nhanh nha