Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Đặt : \(A=2+2^2+2^3+2^4+...+2^{59}+2^{60}\)
\(=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{59}+2^{60}\right)\)
\(=2.\left(1+2\right)+2^3.\left(1+2\right)+....+2^{59}.\left(1+2\right)\)
\(=2.3+2^3.3+...+2^{59}.3\)
\(=3.\left(2+2^3+....+2^{59}\right)\) chia hết cho 3 .
Vậy \(2+2^2+2^3+2^4+...+2^{59}+2^{60}\) chia hết cho 3 .
Đặt \(A=2+2^2+2^3+2^4+....+2^{59}+2^{60}\)
\(\Leftrightarrow A=\left(2+2^2\right)+\left(2^3+2^4\right)+.....+\left(2^{59}+2^{60}\right)\)
\(\Leftrightarrow A=2\left(1+2\right)+2^3\left(1+2\right)+....+2^{59}\left(1+2\right)\)
\(\Leftrightarrow A=2\cdot3+2^3\cdot3+....+2^{59}\cdot3\)
\(\Leftrightarrow A=3\cdot\left(2+2^3+....+2^{59}\right)\)
Vậy A chia hết cho 3 (đpcm)
*) Chứng mình A \(⋮\)3
Ta có : A= ( 21 + 22 ) + ( 23 + 24 ) + .... + ( 259 + 260)
= 2. ( 1 + 2 ) + 23 . ( 1 + 2) + ... + 259 . ( 1+ 2)
= 2 . 3 + 23 . 3 + .....+ 259 . 3
= 3. (2 + 23 + .... + 259 ) \(⋮\)3
Vậy A \(⋮\)3 => đpcm
Ta có: 2 + 22 + 23 + 24 + ... + 260
= ( 2 + 22 + 23 + 24) + ( 25+ 26 + 27 + 28) + ... + (257 + 258 + 259 + 260)
= 2 ( 1 + 2 + 22 + 23) + 25( 1 + 2 + 22 + 23) + ... + 257( 1 + 2 + 22 + 23)
= 2 . 15 + 25.15 + ... + 257 . 15 = 15 ( 2 + 25 + ... + 257) chia hết cho 3.
Nhớ tick mình đúng nhé!
2+22+23+...+260
=(2+22)+(23+24)+...+(259+260)
=2(1+2)+23.(1+2)+...+259(1+2)
=2.3+23.3+...+259.3
=3(2+23+...+259) chia hết cho 3
=>2+22+23+24+...........+259+260 chia hết cho 3
21+22+23+..............+259+260
=(2+22+23)+..............+(258+259+260)
=2.(1+2+22)+.................+258.(1+2+22)
=2.7+............+258.7
=(2+24+.............+258).7 chia hết cho 7
21+22+23+..............+259+260
=(2+22+23)+..............+(258+259+260)
=2.(1+2+22)+.................+258.(1+2+22)
=2.7+............+258.7
=(2+24+.............+258).7 chia hết cho 7
2A=22+23+24+25+.............+260+261
2A-A=(22+23+24+25+..............+260+261)-(2+22+23+24+............+259+260)
A=261-2
S=(2+22+23+24)+(25+26+27+28)+...+(257+258+259+260)
S=2(1+2+22+23)+25(1+2+22+23)+...+257(1+2+22+23+24)
S=2.15+25.15+...+257.15
S=15(2+25+...+257) chia hết cho 15
Vậy S chia hết chi 15
tich ủng hộ cái nha!!!
đặt A=2+2^2+2^3+2^4+....+2^59+2^60
2.A=2.(2+2^2+2^3+2^4+...+2^59+2^60)
2.A=2^2+2^3+2^4+2^5+...+2^60+2^61
-
A=2+2^2+2^3+2^4+....+2^59+2^60
---------------------------------------------------------
2A-A=A=2^61-2
vậy A=2^61-2
kick cho mình nhé