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A) \(y=5X-\frac{18.2}{18}=13<=>5X-2=13<=>x=3\)
B)\(y=\frac{5x-36}{18}=13<=>\frac{5x}{18}-2=13<=>\frac{5x}{18}=15<=>\frac{x}{18}=3<=>x=54\)
| x + 13 | - 13 = 25 - 32
| x + 13 | = -7 + 13
| x + 13 | = 6
TH1:x + 13 = 6
=> x = -7
TH2:x + 13 = -6
=> x = -19
Ta có
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}=>5^{3x+3}\le5^{18}=>3x+3\le18=>x\le5\)
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
Tìm x
( 5x - 36 ) : 18 = 13
=> 5x - 36 = 234
=> 5x = 234 + 36
=> 5x = 270
=> x = 270 : 5
=> x = 54
\(\left(5x-36\right):18=13\)
\(5x-36=13.18\)
\(5x-36=234\)
\(5x=234+36\)
\(5x=270\)
\(x=\frac{270}{5}\)
\(x=54\)
a)15/8+3/4-5/12
=45+18-10/24
=53/24
b)11/24.12/33+5/6
=11.12/12.2.11.3+5/6
=1/6+5/6
=6/6=1
c)15/8+7/24:5/8
=15/8+7/24.8/5
=15/8+7.8/3.8.5
=15/8+7/15
=đề sai, nếu đúng thì như này
=8/15+7/15
=15/15=1
ta có : \(5^x.5^{\left(x+1\right)}.5^{\left(x+2\right)}\le\dfrac{100...0}{2^{18}}\) \(\Leftrightarrow5^{3x+3}\le\dfrac{10^{18}}{2^{18}}=5^{18}\)
\(\)\(\Leftrightarrow3x+3\le18\Leftrightarrow x\le5\) vậy \(x\le5\)
18-(2-x)=5-(-13)
18-(2-x)=18
2-x=18-18=0
x=2-0=-2
Chị nhấn nhầm nhé x=2-0=2 nhé
### Già ###