Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a: \(A=\left(\dfrac{15}{34}+\dfrac{9}{34}-1-\dfrac{15}{17}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\left(\dfrac{12}{17}-1-\dfrac{15}{17}\right)+1\)
\(=\dfrac{-20}{17}+1=\dfrac{-3}{17}\)
b: \(B=\dfrac{-5}{3}\cdot16\dfrac{2}{7}-\dfrac{-5}{3}\cdot28\dfrac{2}{7}\)
\(=\dfrac{-5}{3}\left(16+\dfrac{2}{7}-28-\dfrac{2}{7}\right)=\dfrac{-5}{3}\cdot\left(-12\right)=20\)
c: \(C=25\cdot\dfrac{-1}{27}+\dfrac{1}{5}-2\cdot\dfrac{1}{4}-\dfrac{1}{2}\)
\(=\dfrac{-25}{27}+\dfrac{1}{5}-1\)
\(=\dfrac{-125+27-135}{135}=\dfrac{-233}{135}\)
\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{8}-\frac{3}{5}+\frac{3}{7}}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{4}+\frac{1}{2}+\frac{3}{10}}\)
\(\Rightarrow A=\frac{\frac{1}{2}-\frac{1}{5}+\frac{1}{7}}{3.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{7}\right)}+\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{5}}{\frac{3}{2}.\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{5}\right)}\)
\(\Rightarrow A=\frac{1}{3}+\frac{2}{3}\)
\(\Rightarrow A=1\)
\(\frac{3}{5}\cdot16\frac{5}{7}-\frac{3}{5}\cdot26\frac{5}{7}\)
\(\Rightarrow=\frac{3}{5}\cdot\left(16\frac{5}{7}-26\frac{5}{7}\right)\)
\(\Rightarrow=\frac{3}{5}\cdot\left(\frac{117}{7}-\frac{187}{7}\right)\)\(=\frac{3}{5}\cdot\left(-\frac{70}{7}\right)\)\(=\frac{3}{5}\cdot\left(-10\right)=-\frac{30}{5}=-6\)
\(\frac{3}{5}\cdot16\frac{5}{7}-\frac{3}{5}\cdot26\frac{5}{7}\)
\(=\frac{3}{5}\cdot\left(16\frac{5}{7}-26\frac{5}{7}\right)\)
\(=\frac{3}{5}\cdot\left(-10\right)\)
\(=\frac{-30}{5}=\frac{-6}{5}\)