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a) \(\frac{1.3+3.5+5.7+7.9}{3.6+9.10+15.14+21.18}\)
= \(\frac{1.3+3.5+5.7+7.9}{1.3.2.3+3.5.2.3+5.7.2.3+7.9.2.3}\)
= \(\frac{1.3+3.5+5.7+7.9}{1.3.6+3.5.6+5.7.6+7.9.6}\)
= \(\frac{1.3+3.5+5.7+7.9}{6.\left(1.3+3.5+5.7+7.9\right)}=\frac{1}{6}\)
Dấu "." là dấu nhân cấp 2
b) \(\frac{1.2+2.3+3.4+4.5}{3.6+6.9+9.12+12.15}\)
= \(\frac{1.2+2.3+3.4+4.5}{1.2.3.3+2.3.3.3+3.4.3.3+4.5.3.3}\)
= \(\frac{1.2+2.3+3.4+4.5}{1.2.9+2.3.9+3.4.9+4.5.9}\)
= \(\frac{1.2+2.3+3.4+4.5}{9.\left(1.2+2.3+3.4+4.5\right)}=\frac{1}{9}\)
Dấu "." là dấu nhân cấp 2
c) \(\frac{0,3+\frac{3}{7}+\frac{3}{11}}{0,4+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{\frac{3}{10}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{10}+\frac{4}{7}+\frac{4}{11}}\)= \(\frac{3.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)
\(\frac{1.2.3.4.5.6.7.8.9}{10.2.3.4.5.6.7.8.9}\)
Rút gọn bằng:
\(\frac{1.2.3.4.5.6.7.8.9}{10.2.3.4.5.6.7.8.9}\)\(=\frac{1}{10}\)
1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 = 362880
10 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 = 3628800
2 * x + 14 * (34-9) = 900
2 * x + 14 * 25 = 900
2 * x + 350 = 900
2 * x = 550
x = 550 : 2
x = 275
97 - x =486 : 27
97 - x = 18
x= 97 - 18
x = 79
9 * x - 4 * x = 24 * 5
9 * x - 4 * x = 120
( 9 - 4 ) * x = 120
5 * x =120
x= 120 :5
x =24
dài v ~
4/3 * (7/2 - 5/4 ) - 3/4 * x =2
4/3 * 9/4 - 3/4 * x = 2
3 - 3/4 * x = 2
9/4 * x =2
x = 2 : 9/4
x = 8/9
~~~~~~~~~~
5/3 * x - 3/4 * x + 4/3 = 11/6
( 5/3- 3/4 ) * x + 4/3 =11/6
11/12 * x + 4/3 = 11/6
11/12 * x = 11/6 - 4/3
11/12 * x = 1/2
x= 1/2 : 11/12
x=6/11
dài quá mức bấm mãi ~
Tìm x:
a)
2 * x + 14* ( 34 - 9 ) = 900
2* x + 14 * 25 = 900
2*x + 350 = 900
2*x = 900 - 350
2*x = 550
x = 550 : 2
x = 275
b)
97 - x = 486: 27
97 - x = 18
x = 97 - 18
x = 79
c) 9 * x - 4 * x = 24 * 5
x - ( 9* 4 ) = 120
x - 36 = 120
x = 120 + 36
x = 156
Ủng hộ nha! ^.^
a: \(\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}\right):\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{1}{15}\right)\)
\(=\dfrac{5+3+2}{30}:\dfrac{5+3-2}{30}\)
\(=\dfrac{10}{30}\cdot\dfrac{30}{6}\)
\(=\dfrac{10}{6}=\dfrac{5}{3}\)
b: \(\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}\right):\left(\dfrac{1}{4}-\dfrac{1}{6}\right)\)
\(=\dfrac{30-20+15-12}{60}:\dfrac{3-2}{12}\)
\(=\dfrac{13}{60}\cdot\dfrac{12}{1}=\dfrac{13}{5}\)
\(\frac{\frac{1}{6}+\frac{1}{10}+\frac{1}{15}}{\frac{1}{6}+\frac{1}{10}-\frac{1}{15}}=\frac{\frac{5+3+2}{30}}{\frac{5+3-2}{30}}=\frac{\frac{1}{3}}{\frac{1}{5}}=1\frac{2}{3}\)
\(\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}}{\frac{1}{4}-\frac{1}{6}}=\frac{\frac{30-20+15-12}{60}}{\frac{3-2}{12}}=\frac{\frac{13}{60}}{\frac{1}{12}}=2\frac{3}{5}\)
tíc nha mn, mình đang bị âm điểm
\(1+1+1+1+1+1+1+....+1\)
\(=1.10000\)
\(=10000\)
\(2+2+2+2+2+2+2+....+2\)
\(=2.10000\)
\(=20000\)
\(0+1+2+3+4+5+6+7+8+9+.....+10000\)
Số số hạng của dãy là:
(10000-0):1+1=10001( số )
Tổng của dãy là:
(10000+0).10001:2=50005000
\(\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{9x10}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{2}-\frac{1}{10}\)
\(=\frac{2}{5}\)
đặt A=1/2*3+1/3*4+1/4*5..............1/9*10
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{2}-\frac{1}{10}\)
\(=\frac{4}{10}=\frac{2}{5}\)