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\(\frac{1}{6}+\frac{5}{6}=\frac{6}{6}=1\)
\(\frac{25}{5}+\frac{2}{6}=\frac{150}{30}+\frac{10}{30}=\frac{160}{30}=\frac{32}{6}=\frac{16}{3}\)
\(\frac{12}{5}+\frac{6}{9}=\frac{108}{45}+\frac{30}{45}=\frac{138}{45}\)
\(\frac{2010}{2011}< \frac{2011}{2012}\)
\(\frac{11}{12}=\frac{22}{24}\)
\(\frac{25}{30}>\frac{25}{49}\)
\(\frac{1}{5}< \frac{3}{8}\)
\(\frac{1995}{1997}< \frac{1995}{1996}\)
a, \(\frac{5}{11}\times\frac{7}{25}+\frac{15}{11}\times\frac{1}{5}\)
\(=\frac{5}{11}\times\frac{7}{25}+\frac{5}{11}\times\frac{3}{5}\)
\(=\frac{5}{11}\times\left(\frac{7}{25}+\frac{3}{5}\right)\)
\(=\frac{5}{11}\times\frac{22}{25}\)
\(=\frac{2}{5}\)
b, \(\frac{3}{7}\times\frac{25}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\frac{75}{19}-\frac{1}{7}\times\frac{18}{19}\)
\(=\frac{1}{7}\times\left(\frac{75}{19}-\frac{18}{19}\right)\)
\(=\frac{1}{7}\times3\)
\(=\frac{3}{7}\)
Tính
\(\frac{15}{25}+\frac{80}{125}+\frac{12}{42}+\frac{78}{100}+\frac{18}{12}\)
\(\frac{3}{5}+\frac{16}{25}+\frac{6}{21}+\frac{39}{50}+\frac{3}{2}\)
\(\frac{15}{25}+\frac{16}{25}+\frac{39}{50}+\frac{6}{21}+\frac{3}{2}\)
\(\frac{62}{50}+\frac{39}{50}+\frac{12}{42}+\frac{63}{42}\)
\(\frac{101}{50}+\frac{75}{42}\)
\(\frac{4242}{2100}+\frac{3750}{2100}\)
\(\frac{7992}{2100}\)
\(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}=\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}=1+\frac{3}{5}=\frac{8}{5}\)
\(\frac{3}{2}+\frac{2}{3}+\frac{4}{3}=\left(\frac{2}{3}+\frac{4}{3}\right)+\frac{3}{2}=2+\frac{3}{2}=\frac{7}{2}\)
\(\frac{3}{5}+\frac{7}{5}+\frac{3}{4}=\left(\frac{3}{5}+\frac{7}{5}\right)+\frac{3}{4}=2+\frac{3}{4}=\frac{11}{4}\)
Ta có: \(\frac{54}{11}.\frac{121}{27}< n< \frac{100}{21}:\frac{25}{126}\)
\(\Rightarrow\frac{2.11}{1.1}< n< \frac{100}{21}.\frac{126}{25}\)
\(\Rightarrow22< n< 24\)
\(\Rightarrow n=23\)
Ta có:
\(\frac{54}{11}\cdot\frac{121}{27}=\frac{54\cdot121}{11\cdot27}=22\)
\(\frac{100}{21}:\frac{25}{126}=\frac{100}{21}\cdot\frac{126}{25}=\frac{100\cdot126}{21\cdot25}=24\)
\(\Rightarrow22< n< 24\)
\(\Rightarrow x=23\)
đáp án là B
ý B nhé bạmn