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21 tháng 7 2016

\(A=\frac{1}{5}+\frac{1}{13}+\frac{1}{25}+...+\frac{1}{2.n^2+2n+1}< \frac{1}{4}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{2.n^2+2n}\)

\(A< \frac{1}{2}.\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{n.\left(n+1\right)}\right)\)

\(A< \frac{1}{2}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{n.\left(n+1\right)}\right)\)

\(A< \frac{1}{2}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-...+\frac{1}{n}-\frac{1}{n+1}\right)\)

\(A< \frac{1}{2}.\left(1-\frac{1}{n+1}\right)< \frac{1}{2}\)

\(\Rightarrow A< \frac{1}{2}\)

18 tháng 7 2016

\(A=\frac{1}{5}+\frac{1}{13}+\frac{1}{25}+...+\frac{1}{2.n^2+2n+1}< \frac{1}{4}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{2.n^2+2n}\)

\(A< \frac{1}{2}.\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{n.\left(n+1\right)}\right)\)

\(A< \frac{1}{2}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{n.\left(n+1\right)}\right)\)

\(A< \frac{1}{2}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{n}-\frac{1}{n+1}\right)\)

\(A< \frac{1}{2}.\left(1-\frac{1}{n+1}\right)< \frac{1}{2}\)

=> \(A< \frac{1}{2}\)

5 tháng 7 2018

Ta có: \(n^2+\left(n+1\right)^2>2n\left(n+1\right)\)

\(\Rightarrow\frac{1}{5}+\frac{1}{13}+...+\frac{1}{n^2+\left(n+1\right)^2}\)

\(=\frac{1}{1^2+2^2}+\frac{1}{2^2+3^2}+...+\frac{1}{n^2+\left(n+1\right)^2}< \frac{1}{2.1.2}+\frac{1}{2.2.3}+...+\frac{1}{2.n.\left(n+1\right)}\)

\(=\frac{1}{2}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{n.\left(n+1\right)}\right)\)

\(=\frac{1}{2}.\left(1-\frac{1}{n+1}\right)< \frac{1}{2}\)

17 tháng 10 2018

\(a,M=\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{n^2}\)

\(M< \dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{\left(n-1\right)n}\)

\(M< 1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{n-1}-\dfrac{1}{n}\)

\(M< 1-\dfrac{1}{n}< 1\)

\(\Rightarrow M< 1\left(đpcm\right)\)

\(b,N=\dfrac{1}{4^2}+\dfrac{1}{6^6}+\dfrac{1}{8^2}+...+\dfrac{1}{\left(2n\right)^2}\)

\(N< \dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+...+\dfrac{1}{\left(2n-1\right)\left(2n+1\right)}\)

\(N< \dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{2n-1}-\dfrac{1}{2n+1}\)

\(N< \dfrac{1}{3}-\dfrac{1}{2n+1}< \dfrac{1}{3}\)

\(c,\)\(a< b\Rightarrow2a< a+b\)

\(c< d\Rightarrow2c< c+d\)

\(m< n\Rightarrow2m< m+n\)

\(\Rightarrow2a+2c+2m=2.\left(a+c+m\right)< a+b+c+d+m+n\)

\(\Rightarrow\dfrac{a+c+m}{a+b+c+d+m}< \dfrac{1}{2}\)