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\(A=x^2+2xy+y^2-4x-4y+1=\left(x+y\right)^2-4\left(x+y\right)+1=3^2-12+1=-2\)
\(B=x^2-2xy+y^2-5x+5y+6=\left(x-y\right)^2-5\left(x-y\right)+6=7^2-5.7+6=20\)
a)Ta có
A=\(x^2+2xy+y^2-4x-4y+1\)
=>A=\(\left(x+y\right)^2-4\left(x+y\right)+1\)
Mà x+y=3 nên
A=\(3^2-4\cdot3+1\)
A=-2
b)Ta có:
B=\(x^2-2xy+y^2-5x+5y+6\)
B=\(\left(x-y\right)^2-5\left(x-y\right)+6\)
Mà x-y=7 nên
B=\(7^2-5\cdot7+6\)
B=20
a,x2-z2+y2-2xy
=(x2-2xy+y2)-z2
=(x-y)2-z2
b,-x-y2+x2-y
=(x2-y2)-(x+y)
=(x-y)(x+y)-(x+y)
=(x+y)(x-y-1)
c,x2-2xy-4z2+y2
=(x2-2xy+y2)-(2z)2
=(x-y)2-(2z)2
=(x-y-2z)(x-y+2z)
d,x(x+y)-5x-5y
=x(x+y)-5(x+y)
=(x+y)(x-5)
e, x2 - 5x + 5y - y2
=(x2-y2)-5(x-y)
=(x+y)(x-y)-5(x+y)
=(x+y)(x-y-5)
f, x2 + 4x + 3
=x2+x+3x+3
=x(x+1)+3(x+1)
=(x+1)(x+3)
g, 10x ( x - y) - 8 (y - x)
=10x(x-y)+8(x-y)
=2(x-y)(5x+4)
h, x2 - 3x + 2
=x2-x-2x+2
=x(x+1)-2(x-1)
=(x+1)(x-2)
3x^2(5x^2-7x+4)
=15x^4-21x^3+12x^2
xy^2(2x^2y-5xy+y)
=2x^3y^3-5x^2y^3+xy^3
(2x^2-5x)(3x^2-2x+1)
=6x^4-4x^3+2x^2-15x^3+10x^2-5x
=6x^4-19x^3+12x^2-5x
(x-3y)(2xy+y^2+x)
=2x^2y+xy^2+x^2-6xy^2-3y^3-3xy
=-3y^3+2x^2y-5xy^2+x^2-3xy
a) \(\left(x^2-2xy+y^2\right).\left(x-y\right)\)
\(=\left(x-y\right)^2.\left(x-y\right)\)
\(=\left(x-y\right)^3\)
\(=x^3-3x^2y+3xy^2-y^3.\)
b) \(\left(30x^4y^3-25x^2y^3-4x^4y^4\right):5x^2y^2\)
\(=\left(30x^4y^3:5x^2y^2\right)-\left(25x^2y^3:5x^2y^2\right)-\left(4x^4y^4:5x^2y^2\right)\)
\(=6x^2y-5y-\frac{4}{5}x^2y^2.\)
Chúc bạn học tốt!
a,\(xy+3x-7y-21\)
\(=x\left(y+3\right)-7\left(y+3\right)\)
\(=\left(y+3\right)\left(x-7\right)\)
\(b,2xy-15-6x+5y\)
\(=\left(2xy-6x\right)+\left(-15+5y\right)\)
\(=2x\left(y-3\right)-5\left(3-y\right)\)
\(=2x\left(y-3\right)+5\left(y-3\right)\)
\(=\left(y-3\right)\left(2x+5\right)\)
Bài 1: Thực hiện phép tính
a) 3x(2x2 - 5x + 9) = \(6x^3-15x^2+27x\)
b) 5x(x2-xy+1) = \(5x^3-5xy+5x\)
c) -2/3x2y(3xy-x2+y) = \(-2x^3y^2+\dfrac{2}{3}x^4y-\dfrac{2}{3}x^2y^2\)
2) Thực hiện phép tính
a) (5x-2y) (x2-xy+1) = \(5x^3+5x-7y-2x^3y+2xy^2\)
b) (x+3y)(x2-2xy+y) = \(x^3-x^2y+xy+6xy^2+y^2\)
c) (3x-5y) (4x+ 7y) = \(12x^2-xy-35y^2\)
Bài 3: Rút gọn các biểu thức sau(bằng cách khai triển hằng đẳng thức):
a) (x+y)2+(x-y)2
= \(x^2+2xy+y^2+x^2-2xy+y^2\)
= \(\left(x^2+x^2\right)+\left(2xy-2xy\right)+\left(y^2+y^2\right)\)
= \(2x^2+2y^2=2\left(x^2+y^2\right)\)
b) (x+2)(x-2)-(x-3)(x+1)
= \(x^2-4\) - \(\left(x^2-2x-3\right)\)= \(x^2-4-x^2+2x+3\)
= \(\left(x^2-x^2\right)+2x+\left(-4+3\right)\)=\(2x-1\)
c) (x-2)(x+2)-(x-2)2
=>\(x^2-4-\left(x^2-2.x.2+2^2\right)=x^2-4-x^2-4x+4=\left(x^2-x^2\right)+\left(-4+4\right)-4x=-4x\)
d) (2x+y)(4x2-2xy+y2)-(2x-y)(4x2+2xy+y2)
= \(8x^3+y^3-\left(8x^3-y^3\right)\)
= \(8x^3+y^3-8x^3+y^3\)
= \(\left(8x^3-8x^3\right)+\left(y^3+y^3\right)\)= \(2y^3\)
\(2xy+5x^2y-x^3y=xy\left(2+5x-x^2\right)\)