Giải hệ phương trình:
a)\(\left\{{}\begin{matrix}80x+81y=12,1\\x+y=0,15\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}7x+y=1,03\\3,3x-y=0\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}x+y=0,2\\400\left(0,5x-y\right)+152\cdot3y=32,8\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}69x+57y=16,65\\x+y=0,25\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}69x+8y=8,1\\1,5x+y=0,3\end{matrix}\right.\)
f)\(\left\{{}\begin{matrix}107x+90y=1,97\\x+y=0,02\end{matrix}\right.\)
g)\(\left\{{}\begin{matrix}24x+56y=6,4\\x+y=0,2\end{matrix}\right.\)
h)\(\left\{{}\begin{matrix}69x-y=6,8\\1,5+y=0,25\end{matrix}\right.\)
i)\(\left\{{}\begin{matrix}24x+56y=5,2\\x+y=0,15\end{matrix}\right.\)
k)\(\left\{{}\begin{matrix}16x+96y=16\\104x+96y+58z=30,6\\88x+96y+58z=29\end{matrix}\right.\)
l)\(\left\{{}\begin{matrix}x=40\\x+1,5=0,8\end{matrix}\right.\)
m)\(\left\{{}\begin{matrix}80x+160y=8\\135x+325y=15,7\end{matrix}\right.\)
n)\(\left\{{}\begin{matrix}0,5x+y=0,4\\36,5x+98y=11,47\end{matrix}\right.\)
help
Đặt : \(n_{Fe}=a\left(mol\right),n_{Zn}=b\left(mol\right)\)
\(\Rightarrow56a+65b=18,6\left(g\right)\)
Các PTHH :
\(FeO+H_2\rightarrow Fe+H_2O\)
\(ZnO+H_2\rightarrow Zn+H_2O\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(Bte:2x+2y=\dfrac{6,72}{22,4}.2\left(2\right)\)
Từ(1),(2) \(\Rightarrow\left\{{}\begin{matrix}a=0,1\left(mol\right)=n_{FeO}\\b=0,2\left(mol\right)=n_{ZnO}\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m_{FeO}=0,1.72=7,2\left(g\right)\\m_{ZnO}=0,2.81=16,2\left(g\right)\end{matrix}\right.\)
b) \(m_{ddspu}=18,6+200-0,3.2=218\left(g\right)\)
Theo Pt : \(n_{Zn}=n_{ZnCl2}=0,2\left(mol\right)\)
\(C\%_{ZnCl2}=\dfrac{0,2.136}{218}.100\%=12,48\%\)
Chúc bạn học tốt