Tìm X:
a, 3(2-X)+5(X-6)=98
b,3X-2=2X-3
c,(X-7)(X^3-8)=0
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a, <=> x2 -2x +1 + 5x -x2 =8
<=> 3x +1 =8
<=> 3x = 7
<=> x= 7/3
b, thiếu đề
c, <=> 2x3 -1 + 2x(4 -x2) = 7
<=> 2x3 + 8x -23 = 8
<=> 8x =8
<=> x=1
a: \(\Leftrightarrow\left(x+2\right)\left(12-x\right)=0\)
\(\Leftrightarrow x\in\left\{-2;12\right\}\)
b: \(\Leftrightarrow\left(2x+5\right)\left(x-1\right)=0\)
\(\Leftrightarrow x\in\left\{-\dfrac{5}{2};1\right\}\)
a: Ta có: \(3\left(2x-3\right)+2\left(2-x\right)=-3\)
\(\Leftrightarrow6x-9+4-2x=-3\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
a) `3(2-x)+5(x-6)=-98`
`6-3x+5x-30=-98`
`-3x+5x=-98-6+30`
`2x=-74`
`x=-37`
b) `(x+7)(8-x)=0`
\(\left[{}\begin{matrix}x+7=0\\8-x=0\end{matrix}\right.\\ \left[{}\begin{matrix}x=-7\\x=8\end{matrix}\right.\)
a, \(3\left(2-x\right)+5\left(x-6\right)=-98\)
\(6-3x+5x-30=-98\)
\(2x-24=-98\)
\(2x=-74\)
\(x=-37\)
b,\(\left(x+7\right)\left(8-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-7\\x=8\end{matrix}\right.\)
-Chúc bạn học tốt-
a: Ta có: \(4\left(2-x\right)+x\left(x+6\right)=x^2\)
\(\Leftrightarrow8-4x+x^2+6x-x^2=0\)
\(\Leftrightarrow2x=-8\)
hay x=-4
b: Ta có: \(x\left(x-7\right)-\left(x-2\right)\left(x+5\right)=0\)
\(\Leftrightarrow x^2-7x-x^2-3x+10=0\)
\(\Leftrightarrow-10x=-10\)
hay x=1
c: Ta có: \(\left(2x+3\right)\left(3-2x\right)+\left(2x-1\right)^2=2\)
\(\Leftrightarrow9-4x^2+4x^2-4x+1=2\)
\(\Leftrightarrow-4x=-8\)
hay x=2
\(a,\) \(5x\left(4-x\right)+\left(5x^2-12\right)=x+6\)
\(< =>20x-5x^2+5x^2-12-x-6=0\)
\(< =>19x-18=0\)
\(< =>x=\dfrac{18}{19}\)
\(b,\left(2x-7\right)\left(5+4x\right)-8\left(x^2-4x+5\right)=-30\)
\(< =>10x+8x^2-35-28x-8x^2+24x-40+30=0\)
\(< =>6x-45=0< =>x=\dfrac{45}{6}=7,5\)
a) \(5x\left(4-x\right)+\left(5x^2-12\right)=x+\Rightarrow6\\ \Leftrightarrow20x-5x^2+5x^2-12=x+6\\ \Leftrightarrow20x-12=x+6\\\Rightarrow20x-x=6+12\\ \Rightarrow19x=18\\ \Rightarrow x=\dfrac{18}{19}\)
b) \(\left(2x-7\right)\left(5+4x\right)-8\left(x^2-3x+5\right)=-30\\ \Rightarrow10x+8x^2-35-28x-8x^2+24x-40=-30\\ \Rightarrow6x-75=-30\\ \Rightarrow6x=45\\ \Rightarrow x=\dfrac{15}{2}\)
1: =>(x+3)(x-5)=0
=>x=5 hoặc x=-3
2: =>(x-1)(5x-1)=0
=>x=1/5 hoặc x=1
5: =>(x-4)*x=0
=>x=0 hoặc x=4
10: =>(x+5)(x-3)=0
=>x=3 hoặc x=-5
9: =>(x-2)(x-4)=0
=>x=2 hoặc x=4
7: =>(x-6)(2x-1)=0
=>x=1/2 hoặc x=6
8: =>(2x-1)(3x-12)=0
=>x=4 hoặc x=1/2
a) \(3\left(2-x\right)+5\left(x-6\right)=98\)
\(\Rightarrow6-3x+5x-30=98\)
\(\Rightarrow\left(6-30\right)+\left(-3x+5x\right)=98\)
\(\Rightarrow-24+2x=98\)
\(\Rightarrow2x=98-\left(-24\right)\)
\(\Rightarrow2x=122\)
\(\Rightarrow x=122:2\)
\(\Rightarrow x=61\)
Vậy x = 61
b) \(3x-2=2x-3\)
\(\Rightarrow3x-2x=2-3\)
\(\Rightarrow x=-1\)
Vậy x = -1
c) \(\left(x-7\right)\left(x^3-8\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-7=0\\x^3-8=0\end{cases}}\Rightarrow\orbr{\begin{cases}x-7=0\\x^3=8\end{cases}}\Rightarrow\orbr{\begin{cases}x=7\\x=2\end{cases}}\)
Vậy x = 7 hoặc x = 2
_Chúc bạn học tốt_
a.6-3X+5X-30=98
2X-24=98
2X=74
X=37
b.3X-2X=2-3
X=-1
c.X-7=0 X=7
X^3-8=0 X=2