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a, => x-2x = 15+25
=> -x=40
=> x=-40
b, => -5x^2+50x = -3x-30x = -33x
=> 5x^2-50x=33x
=> 5x^2-50x-33x=0
=> 5x^2-83x=0
=> x.(5x-83) = 0
=> x=0 hoặc 5x-83=0
=> x=0 hoặc x=83/5
Tk mk nha
A/ 15+(3-x)=-10
15+3-x=-10
18-x=-10
-x=-10-18=-8
Suy ra x= 8
a, 15 + (3-x) = -10
3-x = -10 - 15
3-x = -25
x = 3 - (-25)
x = -28
b, 11 - ( 53 + x ) = 97
53 + x = 11 - 97
53 + x = -86
x = -86 - 53
x = -139
c, 5x - (-25) = 35
5x =35 + ( -25)
5x = 10
x = 10 : 5
x = 2
a) Ta có: \(18-x=58-\left(-30\right)\)
\(\Leftrightarrow18-x=88\)
\(\Leftrightarrow x=18-88=-70\)
Vậy: x=-70
b) Ta có: \(x-27=\left(-43\right)-9\)
\(\Leftrightarrow x-27=-43-9\)
\(\Leftrightarrow x-27=-52\)
\(\Leftrightarrow x=-25\)
Vậy: x=-25
c) Ta có: \(169-\left(x+4\right)=69\)
\(\Leftrightarrow x+4=169-69\)
\(\Leftrightarrow x+4=100\)
\(\Leftrightarrow x=96\)
Vậy: x=96
d) Ta có: \(\left(5x+3\right)-\left(-24+4\right)=33\)
\(\Leftrightarrow5x+3+24-4-33=0\)
\(\Leftrightarrow5x-10=0\)
\(\Leftrightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy: x=2
e) Ta có: \(225-\frac{\left(5x+10\right)}{25}+5=-\left(-20\right)\)
\(\Leftrightarrow225-\frac{5x+10}{25}+5-20=0\)
⇔\(-\frac{5x+10}{25}+210=0\)
\(\Leftrightarrow-\frac{5x+10}{25}=-210\)
⇔\(\frac{5x+10}{25}=210\)
\(\Leftrightarrow5x+10=210\cdot25=5250\)
\(\Leftrightarrow5x=5250-10=5240\)
\(\Leftrightarrow x=1048\)
Vậy: x=1048
Mình làm 5 câu thôi nhé !:
1) \(7^x\cdot49=7^{90}\)
\(\Rightarrow7^x\cdot7^2=7^{90}\)
\(\Rightarrow7^{x+2}=7^{90}\)
\(\Rightarrow x=90-2\)
\(\Rightarrow x=88\)
2) \(2^x\cdot4=128\)
\(\Rightarrow2^x\cdot2^2=2^7\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
3) \(3^x-1=2^4\cdot5\)
\(\Rightarrow3^x=80+1\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
4) \(3^x+15=42\)
\(\Rightarrow3^x=42-15\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
5) \(4\cdot2^x-3=125\)
\(\Rightarrow2^2\cdot2^x=128\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
6)
\(5^x=5^{15}:5^3\\ \Leftrightarrow5^x=5^{15-3}\\ \Leftrightarrow5^x=5^{12}\\ \Leftrightarrow x=12\)
7)
\(4^x=4^{15}:16\\ \Leftrightarrow4^x=4^{15}:4^2\\ \Leftrightarrow4^x=4^{15-2}\\ 4^x=4^{13}\\ \Leftrightarrow x=13\)
8)
\(7^x=7^{20}:7^{10}\\ \Leftrightarrow7^x=7^{20-10}\\ \Leftrightarrow7^x=7^{10}\\ \Leftrightarrow x=10\)
9)
\(11^x=11^{11}:11\\ \Leftrightarrow11^x=11^{11-1}\\ \Leftrightarrow11^x=11^{10}\\ \Leftrightarrow x=10\)
10)
\(3^{15}.3^x=3^{30}\\ \Leftrightarrow3^x=3^{30}:3^{15}\\ 3^x=3^{30-15}\\ \Leftrightarrow3^x=3^{15}\\ \Leftrightarrow x=15\)
a) Ta có : 5 x : 5 2 = 5 2 nên x = 4,
b) Ta có: 5 x + 1 : 5 = 5 4 nên x = 4.
c) Ta có : 4 2 x - 1 : 4 = 4 2 nên x = 2.
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
5x - 25 = 10
5x = 10 + 25
5x = 35
x =35 : 5
x = 7
Vậy x = 7
5x - 25 = 10
5x = 10 + 25
5x = 35
x =35 : 5
x = 7
Vậy x = 7