Question

[datcoder]

Tính:

a) \(\dfrac{2}{3}\times\dfrac{5}{8}+\dfrac{7}{4}\)                              b) \(\dfrac{8}{5}:\left(\dfrac{4}{3}-\dfrac{5}{6}\right)\)                             c) \(\dfrac{3}{4}\times\dfrac{1}{5}-\dfrac{1}{10}\)

Answer 1

[Hà Quang Minh]

a) $\frac{3}{2} \times \frac{5}{8} + \frac{7}{4} = \frac{{15}}{{16}} + \frac{7}{4} = \frac{{15}}{{16}} + \frac{{28}}{{16}} = \frac{{43}}{{16}}$

b) $\frac{8}{5}:\left( {\frac{4}{3} - \frac{5}{6}} \right) = \frac{8}{5}:\left( {\frac{8}{6} - \frac{5}{6}} \right) = \frac{8}{5}:\frac{1}{2} = \frac{8}{5} \times 2 = \frac{{16}}{5}$

c) $\frac{3}{4} \times \frac{1}{5} - \frac{1}{{10}} = \frac{3}{{20}} - \frac{1}{{10}} = \frac{3}{{20}} - \frac{2}{{20}} = \frac{1}{{20}}$