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x4 + 2007x2 + 2006x +2007

T.Thùy Ninh · Accepted Answer

$x^4+2007x^2+2006x+2007$

$=x^4+2007x^2+2007x-x+2007$

$=\left(x^4-x\right)+\left(2007x^2+2007x+2007\right)$

$=x\left(x^3-1\right)+2007\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2007\left(x^2+x+1\right)$

$=\left(x^2+x+1\right)\left(x^2-x+2007\right)$Câu trả lời: $x^4+2007x^2+2006x+2007$

$=x^4+2007x^2+2007x-x+2007$

$=\left(x^4-x\right)+\left(2007x^2+2007x+2007\right)$

$=x\left(x^3-1\right)+2007\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2007\left(x^2+x+1\right)$

$=\left(x^2+x+1\right)\left(x^2-x+2007\right)$