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a) \(=\left(\frac{-337}{100}:\frac{40}{100}\right).\frac{250}{100}=\frac{-337}{40}.\frac{40}{16}=-\frac{337}{16}\)
b) \(=\frac{-1}{8}.\left(-5,3\right).8=\frac{-1}{8}.8.\left(-5,3\right)=-1.\left(-5,3\right)=5,3\)
c) \(=10.\left(-7,9\right)=-79\)
d) \(=-\frac{3}{8}.\frac{13}{3}.\left(-8\right)=\left[-\frac{3}{8}.\left(-8\right)\right].\frac{13}{3}=3.\frac{13}{3}=13\)
a)(-3,37:0,4).2,5
=(-8,425).2,5
=-21,0625
b) (-0,125) . (-5,3) . 8
=(-0,125).8.(-5,3)
=(-1).(-5,3)
=5,3
c)(-2,5).(-4).(-7,9)
=10.(-7,9)
=-79
d)(-0,375).\(4\frac{1}{3}\).(-2)3
=(-0,375).(-2)3.\(4\frac{1}{3}\)
=3.\(\frac{13}{3}\)
=13
a) (- 6,37 . 0,4) . 2,5
= -6,37 . (0,4 . 2,5)
= -6,37 . 1
= -6,37
b) (-0,125 ) . (-5,3) . 8
= ( - 0,125 . 8) . (-5,3)
= -1 . ( -5,3)
= 5,3
c) ( -2,5) . (-4) . (-7,9)
= ( -2,5 . -4) . (-7,9)
= 10 . (-7,9)
= -79
a) ( - 6,37 x 0,4 ) x 2,5
=-6,37 x (0,4 x 2,5)
=-6,37 x 1
=-6,37
b) ( -0,125 ) x ( -5,3 ) x 8
=(-0,125 x 8) x (-5,3)
=-1 x (-5,3)
=5,3
c) ( -2,5 ) x ( -4 ) x ( -7,9 )
=[(-2,5) x (-4)] x (-7,9)
=10 x (-7,9)
=-79
a)(-6,37x0,4)x2,5=-6,37x(0,4x2,5)=-6,37x1=-6,37
b)(-0,125)x(-5,3)x8=(-0,125x8)x(-5,3)=-1x(-5,3)=5,3
c)(-2,5)x(-4)x(-7,9)=[(-2,5)x(-4)]x(-7,9)=10x(-7,9)=-79
Tính nhanh:
a) (-6,37 × 0,4) × 2,5;
b) (-0,125) × (-5,3) × 8;
c) (-2,5) × (-4) × (-7,9);
d) (-0,375) × 413(−2)3413(−2)3
Hướng dẫn làm bài:
a) (- 6,37 × 0,4) × 2,5
= - 6,37× (0,4 × 2,5)
= - 6,37 × 1 = - 6,37
b) (-0,125) × (-5,3) × 8
= (-0,125 × 8) × (-5,3)
=(-1). (-5,3) = 5,3
c) (-2,5) × (-4) × (-7,9)
= [(-2,5) × (-4)] × (-7,9)
= 10 . (-7,9)
= -79
d) (−0,375).413.(−2)3
=[(−0,375).(−8)].133=[(−0,375).(−8)].133
=3.133=13
a) (-6,37.0,4).2,5
= (0,4.2,5).(-6,37)
= 1. (-6,37)
= -6,37
b) (-0,125).(-5,3).8
= (-0,125.8).(-5,3)
= -1. (-5,3)
= 5,3
c) (-2,5).(-4).(-7,9)
= ((-2,5).(-4)). (-7,9)
= 10. (-7,9)
= -79
d) (-0,375). \(4\frac{1}{3}\). \(\left(-2^3\right)\)
= (-0,375). \(\frac{13}{3}\). (-8)
= ((-0,375).(-8)). \(\frac{13}{3}\)
= 3. \(\frac{13}{3}\)
= 13
2,9 + 3,7 + (-4,2) + (-2,9) + 4,2
(-6,5) . 2,8 + 2,8 . (-3,5)
(-6,37 . 0,4) . 2,5
(-0,125) . (-5,3) . 8
a) [ 2,9+(-2,9)] + [ (-4,2)+4,2]+ 3,7
= 0+0+3,7
= 3,7
b)2,8.[(-6,5)+(-3,5)
= 2,8 . (-10)
= -28
c) - 6,37 . ( 0,4 . 2,5 )
= -6,37.1
= -6,37
d) ( -0,125 . 8) .( -5,3)
= -1. ( -5,3)
= 5,3
xong rồi đó
\(a\))\(2,9+3,7+\left(-4,2\right)+\left(-2,9\right)+4,2\)
\(=3,7\)
\(b\))\(\left(-6,5\right).2,8+2,8.\left(-3,5\right)\)
\(=2,8.\left(-6,5-3,5\right)\)
\(=2,8.\left(-10\right)\)
\(=-28\)
\(c\))\(\left(-6,37.0,4\right).2,5\)
\(=\left(-6,37\right).\left(0,4.2,5\right)\)
\(=-6,37\)
\(d\))\(\left(-0,125\right).\left(-5,3\right).8\)
\(=\left(-5,3\right).\left(-1\right)\)
\(=5,3\)
a) ( -6,37 . 0,4 ) . 2,5
= -6,37 . ( 0,4 . 2,5 )
= -6,37 . 1
= -6,37
b) ( -0,125 ) . ( 5,3 ) . 8
= ( -0,125 . 8 ) . 5,3
= -1 . 5,3
= -5,3
c) ( -2,5 ) . ( -4 ) . ( -7,9 )
= ( -2,5 . -4 ) . -7,9
= -10 . -7,9
= 79
Bài 1: Tìm x
a) Ta có: \(\dfrac{4}{3}:0.8=\dfrac{2}{3}:\left(0.1\cdot x\right)\)
\(\Leftrightarrow\dfrac{2}{3}:\left(\dfrac{1}{10}\cdot x\right)=\dfrac{4}{3}:\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{2}{3}:\left(\dfrac{1}{10}\cdot x\right)=\dfrac{4}{3}\cdot\dfrac{5}{4}=\dfrac{5}{3}\)
\(\Leftrightarrow x\cdot\dfrac{1}{10}=\dfrac{2}{3}:\dfrac{5}{3}=\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)
\(\Leftrightarrow x=\dfrac{2}{5}:\dfrac{1}{10}=\dfrac{2}{5}\cdot10=\dfrac{20}{5}=4\)
Vậy: x=4
b) Ta có: \(\left|x\right|=-1.2\)
mà \(\left|x\right|\ge0\forall x\)
nên \(x\in\varnothing\)
Vậy: \(x\in\varnothing\)
Bài 2: Tính
a) Ta có: \(\left(-2.5\right)\cdot\left(-4\right)\cdot\left(-7.9\right)\)
\(=\left(2.5\cdot4\right)\cdot\left(-7.9\right)\)
\(=-7.9\cdot10=-79\)
b) Ta có: \(\left(-0.375\right)\cdot\dfrac{13}{3}\cdot\left(-2\right)^3\)
\(=\dfrac{3}{8}\cdot8\cdot\dfrac{13}{3}\)
\(=3\cdot\dfrac{13}{3}=13\)
a)
\(\left(-6,37.0,4\right)2,5=\left(-6,37\right).\left(\frac{2}{5}.\frac{5}{2}\right)=1.\left(-6,37\right)=-6,37\)
b)
\(\left(-0,125\right)\left(-5,3\right).8=\left[\left(-\frac{1}{8}\right).8\right]\left(-5,3\right)=\left(-1\right)\left(-5,3\right)=5,3\)
c)
\(\left(-2,5\right).\left(-4\right).\left(-7,9\right)=\left[\left(-\frac{5}{2}\right).\left(-4\right)\right]\left(-7,9\right)=10.\left(-7,9\right)=-79\)
d)
\(\left(-0,375\right).4\frac{1}{3}.\left(-2\right)^3=\left(-\frac{3}{8}\right).\frac{12}{3}.\left(-8\right)=12\)