Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}-0,2\right)\)
= -1,82:4=-0,455
a) \(=\frac{\left(\frac{9}{25}-36\right)}{\frac{19}{5}+\frac{1}{5}}=\frac{\frac{9}{25}-\frac{900}{25}}{\frac{20}{5}}=\frac{-891}{25}:4\)\(=\frac{-891}{25\cdot4}=\frac{-891}{100}=-8,91\)
b) \(=12\cdot\frac{\left(-2\right)^2}{3^2}+\frac{4}{3}=12\cdot\frac{4}{9}+\frac{4}{3}\)\(=\frac{48}{9}+\frac{4}{3}=\frac{48}{9}+\frac{12}{9}=\frac{60}{9}\)
\(\left(25\frac{4}{9}-14\frac{6}{13}\right)-\left(24\frac{7}{13}-15\frac{5}{9}\right)\)
\(=\left(24\frac{7}{13}-14\frac{6}{13}\right)-\left(25\frac{4}{9}-15\frac{5}{9}\right)\)
\(=\frac{131}{13}-\frac{89}{9}\)
\(=\frac{22}{117}\)
\(\dfrac{4}{5}-\dfrac{2}{9}\times\left(-3\right)^2+\dfrac{9}{2}\div3\)
\(=\dfrac{4}{5}-\dfrac{2}{9}\times9+\dfrac{3}{2}\)
\(=\dfrac{4}{5}-2+\dfrac{3}{2}\)
\(=-\dfrac{6}{5}+\dfrac{3}{2}\)
\(=\dfrac{3}{10}\)
\(\dfrac{4}{5}-\dfrac{2}{9}.\left(-3\right)^2+\dfrac{9}{2}:3\)
\(=\dfrac{4}{5}-\dfrac{2}{9}.9+\dfrac{9}{2}.\dfrac{1}{3}\)
\(=\dfrac{4}{5}-2+\dfrac{3}{2}\)
\(=\dfrac{8}{10}-\dfrac{20}{10}+\dfrac{15}{10}\)
\(=\dfrac{3}{10}\)
\(S=\dfrac{3}{4}-\dfrac{1}{4}-\left(\dfrac{7}{3}-\dfrac{9}{2}\right)-\dfrac{5}{6}\)
\(=\left(\dfrac{3}{4}-\dfrac{1}{4}+\dfrac{18}{4}\right)-\left(\dfrac{14}{6}+\dfrac{5}{6}\right)\)
\(=\dfrac{20}{4}-\dfrac{19}{6}=\dfrac{11}{6}\)
\(\sqrt{25}\)= 5 , - \(\sqrt{4}\) = 2 => 5-3*2:9= 5-6:9= 5-\(\dfrac{2}{3}\)= \(\dfrac{13}{3}\)
ta có \(\sqrt{25}-3\sqrt{\dfrac{4}{9}}\)
\(\Rightarrow\sqrt{25}.2\)
\(\Rightarrow5.2=10\)