Question

[Linh Luna]

Tinh gia tri cua cac bieu thuc sau theo 1 cach hop li

a, A= 1/3 × -6/13 × -9/10 × -13/36

b, B= -1/3 × -15/17 × 34/45

c, C=1/3 × 4/5 + 1/3 × 6/5 + 2/3

d, D= -5/6 × 4/19 + -7/12 × 4/19 - 40/57

e, E= 3/7 × 9/26 - 1/14 × 1/13 - 1/7

Answer 1

[Quìn]

a, \(A=\dfrac{1}{3}.\dfrac{-6}{-3}.\dfrac{-9}{10}.\dfrac{-13}{36}\)

\(A=\dfrac{1.\left(-6\right).\left(-9\right).\left(-13\right)}{3.13.10.36}\)

\(A=\dfrac{-1}{10.2}\)

\(A=\dfrac{-1}{20}\)

b, \(B=\dfrac{-1}{3}.\dfrac{-15}{17}.\dfrac{34}{45}\)

\(B=\dfrac{\left(-1\right).\left(-15\right).34}{3.17.45}\)

\(B=\dfrac{2}{3.3}\)

\(B=\dfrac{2}{9}\)

c, \(C=\dfrac{1}{3}.\dfrac{4}{5}+\dfrac{1}{3}.\dfrac{6}{5}+\dfrac{2}{3}\)

\(C=\dfrac{1}{3}.\left(\dfrac{4}{5}+\dfrac{6}{5}\right)+\dfrac{2}{3}\)

\(C=\dfrac{1}{3}.2+\dfrac{2}{3}\)

\(C=\dfrac{2}{3}+\dfrac{2}{3}\)

\(C=\dfrac{4}{3}\)

d, \(D=\dfrac{-5}{6}.\dfrac{4}{19}+\dfrac{-7}{12}.\dfrac{4}{19}-\dfrac{40}{57}\)

\(D=\dfrac{4}{19}.\left(\dfrac{-5}{6}+\dfrac{-7}{12}\right)-\dfrac{40}{57}\)

\(D=\dfrac{4}{19}.\dfrac{-17}{12}-\dfrac{40}{57}\)

\(D=\dfrac{-17}{57}-\dfrac{40}{57}\)

\(D=\dfrac{-57}{57}=-1\)

e, \(E=\dfrac{3}{7}.\dfrac{9}{26}-\dfrac{1}{14}.\dfrac{1}{13}-\dfrac{1}{7}\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\left(\dfrac{1}{14}.\dfrac{1}{13}+\dfrac{1}{7}\right)\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\left(\dfrac{1}{182}+\dfrac{1}{7}\right)\)

\(E=\dfrac{3}{7}.\dfrac{9}{26}-\dfrac{27}{182}\)

\(E=\dfrac{27}{182}-\dfrac{27}{182}\)

\(E=0\)