Question

[masrur]

Tính giá trị biểu thức:

A=\(\frac{\frac{5}{12}+\frac{3}{4}-1}{3-\frac{5}{6}+\frac{2}{3}}\)+\(\frac{\frac{16}{5}+\frac{16}{7}-\frac{16}{9}}{\frac{17}{5}+\frac{17}{7}-\frac{17}{9}}\)

Answer 1

[Võ Đông Anh Tuấn]

A = \(\frac{\frac{\frac{5+3.3-1.12}{12}}{3.6-5+2.2}+}{6}+\frac{16\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}{17\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}=\frac{\frac{\frac{5+9-12}{12}}{18-5+4}}{6}+\frac{16}{17}=\frac{2}{12}.\frac{6}{17}+\frac{16}{17}=\frac{1}{17}.\frac{6}{17}=1\)

Answer 2

[Nguyễn Hưng Phát]

A=\(\frac{\frac{5}{12}+\frac{9}{12}-\frac{12}{12}}{\frac{18}{6}-\frac{5}{6}+\frac{4}{6}}+\frac{16.\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}{17.\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}\right)}\)

=\(\frac{\frac{1}{6}}{\frac{17}{6}}+\frac{16}{17}\)

=\(\frac{1}{17}+\frac{16}{17}\)

=1