Question

[Nguyễn Phương Nhi]

Tính giá trị biểu thức :

C = \(\frac{21^2.14.125}{35^3.6}\)

D = \(\frac{45^3.20^4.18^2}{180^5}\)

Answer 1

[soyeon_Tiểubàng giải]

\(C=\frac{21^2.14.125}{35^3.6}\)

\(C=\frac{\left(3.7\right)^2.2.7.5^3}{\left(5.7\right)^3.2.3}\)

\(C=\frac{3^2.7^2.2.7.5^3}{5^3.7^3.2.3}\)

\(C=\frac{3^2.7^3.2.5^3}{5^3.7^3.2.3}=3\)

\(D=\frac{45^3.20^4.18^2}{180^5}\)

\(D=\frac{\left(5.3^2\right)^3.\left(2^2.5\right)^4.\left(2.3^2\right)^2}{\left(2^2.3^2.5\right)^5}\)

\(D=\frac{5^3.3^6.2^8.5^4.2^2.3^4}{2^{10}.3^{10}.5^5}\)

\(D=\frac{5^7.3^{10}.2^{10}}{2^{10}.3^{10}.5^5}=5^2=25\)