Question

[Flynn]

Tính B = \(\frac{2^2}{1.3}\) . \(\frac{3^2}{2.4}\). \(\frac{4^2}{3.5}\).............\(\frac{150^2}{149.151}\)

Answer 1

[FL.Hermit]

\(B=\frac{\left(2.3.4...150\right)\left(2.3.4...150\right)}{\left(1.2.3...149\right)\left(3.4.5...151\right)}\)

\(B=\frac{\left(1.2.3...149\right).150.2.\left(3.4.5...150\right)}{\left(1.2.3...149\right).\left(3.4.5...150\right).151}\)

\(B=\frac{300}{151}\)

Answer 2

[Flynn]

có thể giải kĩ hơn ko ?