Question

[Chi Quỳnh]

Tính \(A=x^{10}-100.x^9+100.x^8-100.x^7+...+100.x^2-100.x+1\)

tại x=99

Answer 1

[thỏ]

A=x¹⁰-100x⁹+100x⁸-100x⁷+...+100x²-100x+1 tại x=99

=>A=x¹⁰-(x+1)x⁹+(x+1)x⁸-(x+1)x⁷+...+(x+1)x²-(x+1)x+1

A=x¹⁰-x¹⁰-x⁹+x⁹+x⁸-x⁸-x⁷+...+x³+x²-x²-x+1

= 1-x

=1-99

=-98