Question

[nanami]

tìm x

\(\frac{x+4}{2013}\)+ \(\frac{x+3}{2014}\)= \(\frac{x+2}{2015}+\frac{x+1}{2016}\)

Answer 1

[Hoàng Thủy Tiên]

\(\frac{x+4}{2013}+\frac{x+3}{2014}=\frac{x+2}{2015}+\frac{x+1}{2016}\)

\(\Rightarrow\frac{x+4}{2013}+1+\frac{x+3}{2014}+1=\frac{x+2}{2015}+1+\frac{x+1}{2016}+1\)

\(\Rightarrow\frac{x+2017}{2013}+\frac{x+2017}{2014}=\frac{x+2017}{2015}+\frac{x+2017}{2016}\)

\(\Rightarrow\frac{x+2017}{2013}+\frac{x+2017}{2014}-\frac{x+2017}{2015}-\frac{x+2017}{2016}=0\)

\(\Rightarrow\left(x+2017\right)\left(\frac{1}{2013}+\frac{1}{2014}-\frac{1}{2015}-\frac{1}{2016}\right)=0\)

\(Do\)\(\frac{1}{2013}+\frac{1}{2014}-\frac{1}{2015}-\frac{1}{2016}\ne0\)

\(\Rightarrow x+2017=0\)

\(\Rightarrow x=-2017\)

Vậy \(x=-2017\)

Answer 2

[anh ta là ai chấm com chấm mắm chấm...]

bạn bấm vào "đúng 0" là sẽ có đáp án hiện ra