Question

[Trần Hoàng Tùng Anh]

tìm x

b ,3 (x-2) + 2( 3x - 5) = 10

c, 2x - (3x+1) = 5x-2

d, 3x + 2 = (-5) + 6 

Answer 1

[乇尺尺のﾚ]

\(b,3\left(x-2\right)+2\left(3x-5\right)=10\\ \Leftrightarrow3x-6+6x-10=10\\ \Leftrightarrow3x+6x=10+10+6\\ \Leftrightarrow9x=26\\ \Leftrightarrow x=\dfrac{26}{9}\\ c,2x-\left(3x+1\right)=5x-2\\ \Leftrightarrow2x-3x-1=5x-2\\ \Leftrightarrow2x-3x-5x=-2+1\\ \Leftrightarrow-6x=-1\\ \Leftrightarrow x=\dfrac{1}{6}\\ d,3x+2=-5+6 \\ \Leftrightarrow3x=-5+6-2\\ \Leftrightarrow3x=-2\\ \Leftrightarrow x=-\dfrac{1}{3}\)

Answer 2

[Nguyễn Lê Phước Thịnh]

a: =>3x-6+6x-10=10

=>9x=26

=>x=26/9