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3,8 : (x- 1,05) = \(\frac{19}{9}:\frac{1}{3}\)
3,8 : ( x - 1,05) = \(\frac{19}{3}\)
x - 1,05 = \(3,8:\frac{19}{3}=\frac{3}{5}\)
x = \(\frac{3}{5}+1,05=\frac{33}{20}\)
[ 3,8 : ( x + 1,05 ) ] : 1/3 = 2 1/9
19/5 : ( x + 1,05 ) = 21/9 x 1/3
19/5 : ( x + 1,05) = 7/9
x + 1,05 = 19/5 : 7/9
x + 21/20 = 171/35
x = 171/35 - 21/20
x = 228/49
[ 3,8 : ( x + 1,05 ) ] : 1/3 = 2 1/9
=> 3,8 : ( x+1,05) = 19/9 x 1/ 3 = 19/27
=> x + 1,05 = 3,8 : 19/27 = 5,4
=> x= 5,4-1,05 = 4,35
\(3\frac{8}{9}=\frac{3\cdot9+8}{9}=\frac{27+8}{9}=\frac{35}{9}\)
Ok nhé bạn
\(a,x-\frac{5}{6}:1\frac{1}{6}=0,125\)
\(x-\frac{5}{6}:\frac{7}{6}=\frac{1}{8}\)
\(x-\frac{5}{7}=\frac{1}{8}\)
\(x=\frac{1}{8}+\frac{5}{7}\) \(x=\frac{47}{56}\)
\(b,\left(1-\frac{2}{10}+x+\frac{1}{5}\right):\left(1\frac{1}{3}-\frac{2}{3}+3\frac{1}{3}\right)-1=1\frac{1}{2}\)
\(\left(1-\frac{1}{5}+x+\frac{1}{5}\right):\left(\frac{4}{3}-\frac{2}{3}+\frac{10}{3}\right)-1=\frac{3}{2}\)
\(\left(\frac{4}{5}+x+\frac{1}{5}\right):4=\frac{3}{2}+1\)
\(\left(1+x\right):4=\frac{5}{2}\)
\(1+x=\frac{5}{2}.4\)
\(1+x=10\)
\(x=10-1\)
\(x=9\)
[3,8 : (x + 1,05)] : \(\frac{1}{3}\)= 2\(\frac{1}{9}\)
\(\left[\frac{19}{5}:\left(x+\frac{21}{20}\right)\right]:\frac{1}{3}=\frac{19}{9}\)
\(\frac{19}{5}:\left(x+\frac{21}{20}\right)=\frac{19}{9}.\frac{1}{3}=\frac{19}{27}\)
\(x+\frac{21}{20}=\frac{19}{5}:\frac{19}{27}=\frac{27}{5}\)
\(x=\frac{27}{5}-\frac{21}{20}\)
\(x=\frac{87}{20}\)