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các số đó là 5, 15, 25, 35, 45, 55, 65, 75, 85, 95, 105. Chỉ cần nhân các số tận cùng là được. Kết quả là:5
\(\dfrac{10}{3}\cdot\dfrac{1}{2}-\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)+\dfrac{1}{5}=\dfrac{3}{5}:\dfrac{1}{2}\\ \Leftrightarrow\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{10}{3}\cdot\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{3}{5}\cdot2\\ \Leftrightarrow\dfrac{1}{2}x=1\\ \Leftrightarrow x=2\)
Vậy x=2.
\(\dfrac{10}{3}.\dfrac{1}{2}-\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)+\dfrac{1}{5}=\dfrac{3}{5}:\dfrac{1}{2}\\ \dfrac{5}{3}-\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)+\dfrac{1}{5}=\dfrac{6}{5}\\ \dfrac{5}{3}-\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)=\dfrac{6}{5}-\dfrac{1}{5}=1\\ \dfrac{1}{2}.x-\dfrac{1}{3}=\dfrac{5}{3}-1=\dfrac{2}{3}\\ \dfrac{1}{2}.x=\dfrac{2}{3}+\dfrac{1}{3}=1\\ x=1:\dfrac{1}{2}=2\\ Vậy:x=2\)
`(1/(1.3)+1/(3.5)+.......+1/(23.25))xx((x+1)+(x+3)+(x+5)+.....+(x+23))=144`
`(2/(1.3)+2/(3.5)+.......+2/(23.25))xx[(x+x+....+x)+(1+3+5+...+23)]=288`
`(1-1/3+1/3-1/5+.....+1/23-1/25)xx(12x+(24.12)/2)=288`
`(1-1/25)xx(12x+12.12)=288`
`24/25xx[12(x+12)]=288`
`24/25xx(x+12)=28`
`x+12=28:24/25=50`
`x=50-12=38`
Vậy `x=38`
\(x:0,5+x\) . \(\dfrac{1}{5}=1\dfrac{3}{5}\)
\(x :\)\(\dfrac{1}{2}+x.\dfrac{1}{5}=\dfrac{8}{5}\)
\(x . 2+x.\)\(\dfrac{1}{5}=\dfrac{8}{5}\)
\(x\)\((\)\(2+\)\(\dfrac{1}{5}\)\()\) \(=\)\(\dfrac{8}{5}\)
\(x.\)\(\dfrac{11}{5}=\dfrac{8}{5}\)
\(x=\)\(\dfrac{8}{5}:\dfrac{11}{5}\)
\(x=\)\(\dfrac{8}{11}\)
vậy \(x=\)\(\dfrac{8}{11}\)
\(x-1\dfrac{1}{2}=2\dfrac{3}{5}\\ x-\dfrac{3}{2}=\dfrac{13}{5}\\ x=\dfrac{41}{10}\\ \\ \dfrac{1}{3}+\dfrac{12}{5}:x=3\dfrac{2}{3}\\ \dfrac{1}{3}+\dfrac{12}{5}:x=\dfrac{11}{3}\\ \dfrac{12}{5}:x=\dfrac{10}{3}\\ x=\dfrac{18}{25}\\ \\ 3384:94:x=9\\ 36:x=9\\ x=4\)
a: \(x+6\dfrac{1}{8}=8\)
=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)
=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)
b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)
=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)
=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)
c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)
=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)
=>\(x\cdot1=\dfrac{7}{9}\)
=>\(x=\dfrac{7}{9}\)
105:3(x-1)=5
35(x-1)=5
x-1=1/7
x=8/7
105 : 3 . ( x - 1 ) = 5
<=> 35.(x-1) = 5
<=> 35x - 35 = 5
<=> 35x = 5 + 35
<=> 35x = 40
<=> x = 40 : 35
<=> x = 8/7