Câu hỏi của Bùi Khánh Ngọc

Question

tìm x , biết :[ x + 1/2 ] + [ x + 1/4 ] + [ x + 1/8 ] + [ x + 1/16 ] = 23/16

Wall HaiAnh · Accepted Answer

Trả lời$\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\frac{8+4+2+1}{16}=\frac{23}{16}$$\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}$$\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}$$\Leftrightarrow4x=\frac{8}{16}$$\Leftrightarrow4x=\frac{1}{2}$$\Leftrightarrow x=\frac{1}{2}:4$$\Leftrightarrow x=\frac{1}{8}$Vậy x=$\frac{1}{8}$Câu trả lời: Trả lời$\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\left(\frac{8}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\frac{8+4+2+1}{16}=\frac{23}{16}$$\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}$$\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}$$\Leftrightarrow4x=\frac{8}{16}$$\Leftrightarrow4x=\frac{1}{2}$$\Leftrightarrow x=\frac{1}{2}:4$$\Leftrightarrow x=\frac{1}{8}$Vậy x=$\frac{1}{8}$

Nguyễn Thanh Hiền · Answer

$\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\left(\frac{8+4+2+1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}$$\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}$$\Leftrightarrow4x=\frac{1}{2}$$\Leftrightarrow x=\frac{1}{2}:4$$\Leftrightarrow x=\frac{1}{8}$Câu trả lời: $\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\left(\frac{8+4+2+1}{16}\right)=\frac{23}{16}$$\Leftrightarrow4x+\frac{15}{16}=\frac{23}{16}$$\Leftrightarrow4x=\frac{23}{16}-\frac{15}{16}$$\Leftrightarrow4x=\frac{1}{2}$$\Leftrightarrow x=\frac{1}{2}:4$$\Leftrightarrow x=\frac{1}{8}$

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