Question

[Trà My Kute]

Tìm x , biết ;

\(\dfrac{x+1}{2016}+\dfrac{x+2}{2015}=\dfrac{x+3}{2014}+\dfrac{x+4}{2013}\)

Answer 1

[Nguyễn Phạm Thanh Nga]

x =0 nhé bn

Answer 2

[Hoàng Anh Thư]

\(\dfrac{x+1}{2016}+\dfrac{x+2}{2015}=\dfrac{x+3}{2014}+\dfrac{x+4}{2013}\) <=>\(\dfrac{x+1}{2016}+1+\dfrac{x+2}{2015}+1=\dfrac{x+3}{2014}+1+\dfrac{x+4}{2013}+1\) <=>

\(\dfrac{x+2017}{2016}+\dfrac{x+2017}{2015}=\dfrac{x+2017}{2014}+\dfrac{x+2017}{2013}\)

<=>\(\dfrac{x+2017}{2016}+\dfrac{x+2017}{2015}-\dfrac{x+2017}{2014}-\dfrac{x+2017}{2013}=0\)

<=>(x+2017)(1/2016+1/2015-1/2014-1/2013)=0

vì 1/2016+1/2015-1/2014-1/2013 khác 0

nên x+2017=0<=>x=-2017

vậy................

chúc bạn học tốt ^^