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a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
a) 2(x-3)-3(x-5)=4(3-x)-18
2x-6-3x-15=12-4x-18
2x-3x+4x=12-18+6+15
3x=15
x=15:3
x=5
Vậy x=5
a,2x+53=135
2x=135-53
2x=82
x=82:2
x=41
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a) Ta có: \(x-12=\left(-9\right)-15\)
\(\Rightarrow x-12=-24\)
\(\Rightarrow x=-12\)
b) \(2-x=17-\left(-5\right)\)
\(\Rightarrow2-x=22\)
\(\Rightarrow x=2-22\)
\(\Rightarrow x=-20\)
c) \(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Rightarrow-15=x-16\)
\(\Rightarrow x=1\)
d) \(x-\left(17-x\right)=x-7\)
\(\Rightarrow x-17+x=x-7\)
\(\Rightarrow x+x-x=-7+17\)
\(\Rightarrow x=10\)
e) \(9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Rightarrow9-25=7-x-25-7\)
\(\Rightarrow-16=-25-x\)
\(\Rightarrow x=-9\)
g) \(x-13=21-x\)
\(\Rightarrow x+x=21+13\)
\(\Rightarrow2x=34\)
\(\Rightarrow x=17\)
a, x - 12 = ( -9 ) - 15
x - 12 = -24
x = -24 + 12
x = -12
b, 2 - x = 17 - ( -5 )
2 - x = 22
x = 2 - 22
x = -20
c, 11 - ( 15 + 11 ) = x - ( 25 - 9 )
11 - 26 = x - 16
-15 = x - 16
x = -15 + 16
x = 1
d, x - ( 17 - x ) = x - 7
x - 17 + x = x - 7
x + x - 17 = x - 7
x + x - x = -7 + 17
x = 10
e.9 - 25 = ( 7- x ) - ( 25 + 7 )
-16 = ( 7 - x ) -32
7 - x = -32 + 16
7 - x = 16
x = 7 - 16
x= -9
g, x - 13 = 21 - x
x + x = 21 + 13
2x = 44
x = 44 : 2
x=22
a, 2x + 35 -x+27=0
x +62=0
x=-62
b, 2x -41 -3x + 23 =0
-x -18=0
-x=18
x=-18
c, 4x -12-3x-15= -124
x -27=-124
x= -97
d, Suy ra x+3 =0 hoặc 2x-18=0
x=-3 hoặc 2x=18 => x=9
vậy x=-3 hoặc x=9
Lâu rồi mình ko giải, sai thì thôi nhé!
a) \(\left(10-2x\right)^2=25-\left(-11\right)\)'=
\(\Leftrightarrow\left(10-2x\right)^2=36\)
\(\Leftrightarrow\left(10-2x\right)^2=6^2\)
\(\Leftrightarrow\orbr{\begin{cases}10-2x=6\\10-2x=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=10-6\\2x=10-\left(-6\right)\end{cases}\Leftrightarrow}\orbr{\begin{cases}2x=4\\2x=16\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=8\end{cases}}}\)
Vậy \(x\in\left\{2;8\right\}\)
b) \(-2\left(-x+5\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-2\left(5-x\right)-3\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-5\left(5-x\right)=4\left(2+x\right)\)
\(\Leftrightarrow-25+5x=8+4x\)
\(\Leftrightarrow5x-25=8+4x\)
\(\Leftrightarrow5x=8+4x+25\)
\(\Leftrightarrow5x=4x+33\)
\(\Leftrightarrow5x-4x=33\)
\(\Leftrightarrow1x=33\)
\(\Leftrightarrow x=33\)
Vậy \(x=33\)
a) (10 - 2x)2 = 25 - (-11)
(10 - 2x)2 = 36
(10 - 2x)2 = 62
=> 10 - 2x = 6
2x = 10 - 6
2x = 4
x =4:2
x=2
Vậy x = 2
b)-2(-x+5) - 3(5 - x) = 4(2+x)
2x - 10 - 15 +3x = 8 + 4x
2x - 25 + 3x = 8 +4x
2x + 3x - 4x = 8 + 25
5x - 4x = 33
x= 33
Vậy x = 33