Question

[Gia Bảo]

Tìm x: a) (x+1)^3-x(x-2)^+x-1=0

b) (x-1)^3 - (x+3)(x^2-3x+9)+3(x^2-4)=2

Tính: (căn 2 x - y^2)

Answer 1

[HT.Phong (9A5)]

a) Mình ko rõ 

b) \(\left(x-1\right)^3-\left(x+3\right)\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)

\(\Leftrightarrow x^3-3x^2+3x-1-\left(x^3+27\right)+3x^2-12=2\)

\(\Leftrightarrow x^3+3x-13-x^3-27=2\)

\(\Leftrightarrow3x-40=2\)

\(\Leftrightarrow3x=42\)

\(\Leftrightarrow x=14\)

Answer 2

[Nguyễn Thị Thương Hoài]

\(x\)(\(x\) - 2)^? vậy em ha