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\(\dfrac{5}{6}-\dfrac{1}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{2}{5}x=0\Rightarrow\dfrac{1}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{2}{5}x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{1}{2}x-\dfrac{1}{6}-\dfrac{2}{5}x=\dfrac{5}{6}\Rightarrow\dfrac{1}{2}x-\dfrac{2}{5}x=\dfrac{5}{6}+\dfrac{1}{6}=1\)
\(\Rightarrow x\left(\dfrac{1}{2}-\dfrac{2}{5}\right)=1\Rightarrow\dfrac{1}{10}x=1\Rightarrow x=1:\dfrac{1}{10}=10\)
Vậy x = 10
\(A\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\\\Leftrightarrow \left(x-1\right)^{x+4}-\left(x-1\right)^{x+2}=0\\ \Leftrightarrow\left(x-1\right)^{x+2}\left(\left(x-1\right)^{x+2}+1\right)=0\\ \Leftrightarrow\left(x-1\right)^{x+2}=0hoac\left(x-1\right)^{x+2}+1=0\)
Giả tiếp đc x=1
tìm x, biết
a, x-15=1 b,-x-1/2=3/7 c,2x-9=9
x=16 -x=3/7+1/2 2x=18
-x=13/14 x=9
tìm x
/x/=5 /x/=10
x=-5 hoặc x=5 x=-10 hoặc x=10
thực hiện phép tính
tìm 3/5 của 15
3/5 của 15 là 25
tìm 1/4 của 20
1/4 của 20 là 80
a: \(\left|\dfrac{1}{2}x-3\right|=\dfrac{1}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-3=\dfrac{1}{2}\\\dfrac{1}{2}x-3=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x=\dfrac{7}{2}\\\dfrac{1}{2}x=\dfrac{5}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=5\end{matrix}\right.\)
b: \(\left|3x+\dfrac{1}{5}\right|-\dfrac{1}{3}=\dfrac{2}{3}\)
\(\Leftrightarrow\left|3x+\dfrac{1}{5}\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}3x+\dfrac{1}{5}=1\\3x+\dfrac{1}{5}=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=\dfrac{4}{5}\\3x=-\dfrac{6}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{15}\\x=-\dfrac{2}{5}\end{matrix}\right.\)
d: \(\left|\dfrac{1}{2}x-3\right|< \dfrac{1}{2}\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{2}x-3>-\dfrac{1}{2}\\\dfrac{1}{2}x-3< \dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{1}{2}x>\dfrac{5}{2}\\\dfrac{1}{2}x< \dfrac{7}{2}\end{matrix}\right.\Leftrightarrow5< x< 7\)
e: \(\left|3x-\dfrac{4}{5}\right|>\dfrac{1}{3}\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{4}{5}>\dfrac{1}{3}\\3x-\dfrac{4}{5}< -\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x>\dfrac{17}{15}\\3x< \dfrac{7}{15}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x>\dfrac{17}{45}\\x< \dfrac{7}{45}\end{matrix}\right.\)
a,-12(x-5)+7(3-x)=20
-12x+60+21-7x=20
-19x=-61
x=\(\frac{61}{19}\)
b,30(x+1)-3(x-5)-15x=25
30x+30+15-3x-15x=25
12x=-20
x=\(-\frac{20}{12}\)
xy + 2x - y = 5
=> x(y + 2) - y - 2 = 3
=> x(y + 2) - (y + 2) = 3
=> (x - 1)(y + 2) = 3
x-1 | 1 | -1 | 3 | -3 |
y+2 | 3 | -3 | 1 | -1 |
x | 2 | 0 | 4 | -2 |
y | 1 | -5 | -1 | -3 |
\(xy+2x-y=5\)
\(\Leftrightarrow x\left(y+2\right)-\left(y+2\right)=3\)
\(\Leftrightarrow\left(y+2\right)\left(x-1\right)=3\)
\(\Leftrightarrow y+2;x-1\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
Ta có bảng
x-1 | -3 | -1 | 1 | 3 |
x | -2 | 0 | 2 | 4 |
y+2 | -1 | -3 | 3 | 1 |
y | -3 | -5 | 1 | -1 |
6x-12=9x+15
3x=-27
x=-9
6.x = 9.x+15+12
6.x = 9.x+27
27 = 9.x-6.x
27 = 3.x
x = 27 : 3
x = 9
Vậy x = 9
Tk mk nha