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\(y+5x2-\left(32+16x3:6-15\right)=0\)
\(y+10-\left(32+8-15\right)=0\)
\(y+10-\left(40-15\right)=0\)
\(y+10-25=0\)
\(y=25-10\)
\(y=15\)
x : 0,5 + x : 0,125 = 9,78
x : ( 0,5 + 0,125 ) = 9,78
x : 0,625 = 9,78
x = 9,78 x 0,625
x = 6,1125
\(x\div0,5+x\div0,125=9,78\)
\(\Rightarrow x\times2+x\times8=9,78\)
\(\Rightarrow x\left(8+2\right)=9,78\)
\(\Rightarrow10x=9,78\)
\(\Rightarrow x=9,78\div10\)
\(\Rightarrow x=0,978\)
\(a\times2+a:2=5\)
\(a\times2+a\times\dfrac{1}{2}=5\)
\(a\times\left(2+\dfrac{1}{2}\right)=5\)
\(a\times\dfrac{5}{2}=5\)
\(a=5:\dfrac{5}{2}\)
\(a=2\)
Vậy \(a=2\)
\(2,25-\left(5\times a-125:5\right)=0\)
\(2,25-5\times a+25=0\)
\(27,25-5\times a=0\)
\(5\times a=27,25\)
\(a=27,25:5\)
\(a=5,45\)
Vậy a=5,45
4,25 x (X+ 41,53) - 125= 53,5
4,25 x (X+ 41,53)= 53,5+ 125
4,25 x (X+ 41,53) = 178,5
X+ 41,53= 178,5: 4,25
X+ 41,53= 42
X= 42- 41,53
X= 0,47
Tk cho mk nhé ^^
4,25x(X+41,53)-125=53,5
4,25x(X+41,53)=53,5+125
4,25x(X+41,53)=178,5
X+41,53=42
X=0,47
#H
Giải:
\(9-3\times\left(x-9\right)=6\)
\(3\times\left(x-9\right)=9-6\)
\(3\times\left(x-9\right)=3\)
\(x-9=3:3\)
\(x-9=1\)
\(x=1+9\)
\(x=10\)
\(4+6\times\left(x+1\right)=70\)
\(6\times\left(x+1\right)=70-4\)
\(6\times\left(x+1\right)=66\)
\(x+1=66:6\)
\(x+1=11\)
\(x=11-1\)
\(x=10\)
\(\dfrac{x}{13}+\dfrac{15}{26}=\dfrac{46}{52}\)
\(\dfrac{x}{13}=\dfrac{23}{26}-\dfrac{15}{26}\)
\(\dfrac{x}{13}=\dfrac{4}{13}\)
\(\Rightarrow x=4\)
\(\dfrac{11}{14}-\dfrac{3}{x}=\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{11}{14}-\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{3}{7}\)
\(\Rightarrow x=7\)
\(5\times\left(3+7\times x\right)=40\)
\(3+7\times x=40:5\)
\(3+7\times x=8\)
\(7\times x=8-3\)
\(7\times x=5\)
\(x=5:7\)
\(x=\dfrac{5}{7}\)
\(x\times6+12:3=120\)
\(x\times6+4=120\)
\(x\times6=120-4\)
\(x\times6=116\)
\(x=116:6\)
\(x=\dfrac{58}{3}\)
\(x\times3,7+x\times6,3=120\)
\(x\times\left(3,7+6,3\right)=120\)
\(x\times10=120\)
\(x=120:10\)
\(x=12\)
\(\left(15\times24-x\right):0,25=100:\dfrac{1}{4}\)
\(\left(360-x\right):0,25=400\)
\(360-x=400.0,25\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
\(71+65\times4=\dfrac{x+140}{x}+260\)
\(\left(x+140\right):x+260=71+260\)
\(x:x+140:x+260=331\)
\(1+140:x+260=331\)
\(140:x=331-1-260\)
\(140:x=70\)
\(x=140:70\)
\(x=2\)
\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+...+\left(x+28\right)=155\)
\(10\times x+\left(1+4+7+...+28\right)=155\)
Số số hạng \(\left(1+4+7+...+28\right)\) :
\(\left(28-1\right):3+1=10\)
Tổng dãy \(\left(1+4+7+...+28\right)\) :
\(\left(1+28\right).10:2=145\)
\(\Rightarrow10\times x+145=155\)
\(10\times x=155-145\)
\(10\times x=10\)
\(x=10:10\)
\(x=1\)
Đều theo cách lớp 5 nha em!
5x2-120x-125=0
x(5x-120)=0+125
x(5x-120)=125
\(\Rightarrow\orbr{\begin{cases}x=125\\5x-120=125\Rightarrow5x=125-120\Rightarrow5x=5\Rightarrow x=5:5=1\end{cases}}\)
Vậy x=125 hoặc x=1
\(5x^2-120x-125=0\)
\(5\left(x^2-24x-25\right)=0\)
\(5\left(x-25\right)\left(x+1\right)=0\)
\(\Rightarrow5=0\)vô nghiệm
\(\Rightarrow\orbr{\begin{cases}x-25=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=25\\x=-1\end{cases}}}\)