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Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
a) 22 ( x + 32 ) - 5 = 55
=>4(x+9)-5=55
=>4(x+9)=60
=>x+9=15
=>x=6
b)7 ( x + 52 ) - 20 = 190
=>7(x+25)=210
=>x+25=30
=>x=5
c)6 ( x + 23 ) + 40 = 100
=>6(x+8)+40=100
=>6(x+8)=60
=>x+8=10
=>x=2
\(a,\Rightarrow x=19-17=2\\ b,\Rightarrow x+8=28:2=14\\ \Rightarrow x=14-8=6\\ c,\Rightarrow42-x=5^2=25\\ \Rightarrow x=42-25=17\)
a)x=2
b)x+8=14
x=6
c)\(42-x=5^2\)
\(42-x=25\)
\(-x=-17\)
\(x=17\)
`#3107.101107`
\(\left(7x-5\right)^3=8\\ \Rightarrow\left(7x-5\right)^3=2^3\\ \Rightarrow7x-5=2\\ \Rightarrow7x=2+5\\ \Rightarrow7x=7\\ \Rightarrow x=1\)
Vậy, `x = 1.`
a) 25+x=0
x=0-25
x=-25
b)\(2^x:2^{19}=2^{25}\)
\(2^x=2^{25}.2^{19}\)
\(2^x=2^{44}\)
=>x=44
c)\(5^x.5^{18}=5^{54}\)
\(5^x=5^{54}:5^{18}\)
\(5^x=5^{36}\)
=>x=36
a: =>13x-144=25
=>13x=169
hay x=13