Question

[Sawada Tsunayoshi]

Tìm số tự nhiên x biết rằng:

1/3+1/6+1/10+...+2/x(x+1)=99/101

Answer 1

[Cô Hoàng Huyền]

\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{99}{101}\)

\(\Leftrightarrow\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+...+\frac{2}{x\left(x+1\right)}=\frac{99}{101}\)

\(\Leftrightarrow2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{99}{101}\)

\(\Leftrightarrow2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{99}{101}\)

\(\Leftrightarrow2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{99}{101}\)

\(\Leftrightarrow2\left(\frac{1}{2}-\frac{1}{x+1}\right)=\frac{99}{101}\)

\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{99}{202}\)

\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{101}\)

\(\Leftrightarrow x=100\)