Question

[Hoàng Thục Nhi]

tìm số nguyên n để:

(3n+14) chia hết cho (n+2)

Answer 1

[Kado365]

\(3n+14⋮n+2\)

\(\Rightarrow3\left(n+2\right)+8⋮n+2\)

\(\Rightarrow8⋮n+2\)

\(\Rightarrow n+2\in\text{Ư}\left(8\right)\)

\(\Rightarrow n+2\in\text{{}\pm1;\pm2;\pm4;\pm8\text{ }\)

\(\Rightarrow n\in\left\{-1;-3;0;-4;2;-6;6;-10\right\}\)