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#)Giải :
\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.2^4}{3^9.2^3}=3\)
\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
\(A=\frac{3^{10}\left(11+5\right)}{3^9.2^4}\)
\(A=\frac{3^{10}.16}{3^9.2^4}\)
\(A=\frac{3^{10}.2^4}{3^9.2^4}\)
\(A=3\)
b: \(\Leftrightarrow n+1\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(n\in\left\{0;-2;1;-3;3;-5\right\}\)
c: \(\Leftrightarrow n+2\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{-1;-3;3;-7\right\}\)
d: \(\Leftrightarrow n+2\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(n\in\left\{-1;-3;0;-4;2;-6\right\}\)
a: \(\Leftrightarrow n-1\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{2;0;6;-4\right\}\)
\(A=\frac{132639}{173451}\)
\(A=\frac{132639:10203}{173451:10203}\)
\(A=\frac{13}{17}\)
\(B=\frac{16515}{20919}\)
\(B=\frac{16515:1101}{20919:1101}\)
\(B=\frac{15}{19}\)
Bài 6:
\(max_{x-y}=max_x-min_y=11-\left(-89\right)=100\\ min_{x-y}=min_x-max_y=-2-1=-3\)
Bài 7:
\(\Leftrightarrow2\left(a+b+c\right)=11-3-2=6\\ \Leftrightarrow a+b+c=3\\ \Leftrightarrow\left\{{}\begin{matrix}a=3-\left(b+c\right)=6\\b=11-a=5\\c=-3-b=-8\end{matrix}\right.\)
Bài 7:
Ta có:
\(\left(a+b\right)+\left(b+c\right)+\left(a+c\right)=11+\left(-3\right)+\left(-2\right)\\ \Rightarrow2\left(a+b+c\right)=6\\ \Rightarrow a+b+c=3\)
\(\Rightarrow\left\{{}\begin{matrix}a=\left(a+b+c\right)-\left(b+c\right)=3-\left(-3\right)=6\\b=\left(a+b+c\right)-\left(a+c\right)=3-\left(-2\right)=5\\c=\left(a+b+c\right)-\left(a+b\right)=3-11=-8\end{matrix}\right.\)
Bài 2:
a. $=124-52.124+124.47=124(1-52+47)=124(48-52)=124.(-4)=-496$
b. $=55(-78)+13(-78)-65(-78)=(-78)(55+13-65)=(-78).3=-234$
c. $=100(-47)+53(-100)=100(-47)+(-53).100=100[(-47)+(-53)]=100.(-100)=-10000$
d. $=25.75-25.49.3-75.25+75.49$
$=25.75-49.75-75.25+75.49=(25.75-75.25)+(75.49-49.75)=0+0=0$
Bài 3:
a. Ta nhớ quy tắc âm * âm = dương nên:
$(-18)(-13)>0$
$(-15)(-17)>0$
$\Rightarrow (-18)(-13)> (-15)(-17)$ (đpcm)
b.
$(-1)(-2)>0$
$(-3)(-4)>0$
$.....$
$(-17)(-18)>0$
$-19<0$
$\Rightarrow (-1)(-2)...(-18)(-19)<0$
C = \(\frac{2^{10}.13+2^{10}.65}{2^6.104}\)
= \(\frac{2^{10}.\left(13+65\right)}{2^6.104}\)
= \(\frac{2^{10}.78}{2^6.104}\)
= \(\frac{2^6.2^4.78}{2^6.104}\)
= \(\frac{2^6.16.78}{2^6.4.26}\)
= \(\frac{2^6.4.4.26.3}{2^6.4.26}\)
= \(4.3\)
= \(12\)