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Đặt \(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{96}+\frac{2}{192}\)
\(\frac{1}{2}A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)
\(\frac{1}{4}A=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}+\frac{1}{384}\)
\(\frac{1}{2}A-\frac{1}{4}A=\frac{1}{3}-\frac{1}{384}\)
\(\frac{1}{4}A=\frac{127}{384}\)
\(A=\frac{127}{384}.4=\frac{127}{96}\)
\(2A=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}.\)
\(A=2A-A=\frac{4}{3}-\frac{2}{96}=\frac{63}{48}\)
5 x 53 x 12 + 4 x 15 x 87 - 2 x 8 x 30 = 60 x 53 + 60 x 87 - 60 x 8
= 60 x (53 + 87 - 8)
= 60 x 132
= 6 x 10 x 132
= 792 x 10
= 7920
Chúc bạn hok tốt nha!@##
ko đúng thì thui
1 + 6 + 11 + 16 + ... + 45 + 51
số số hạng là : ( 51 - 1 ) : 5 + 1 = 11 ( số )
tổng là : ( 51 + 1 ) x 11 : 2 = 286
làm tương tự nhé. nhiều quá làm ko nổi
1 + 2 + 3 + ... + 98 + 99 + 100
số số hạng là : ( 100 - 1 ) : 1 + 1 = 100 ( số )
tổng là : ( 100 + 1 ) x 100 : 2 = 5050
2 + 4 + 6 + ... + 98 + 100
số số hạng là : ( 100 - 2 ) : 2 + 1 = 50 số
tổng là : ( 100 + 2 ) x 50 : 2 = 2550
\(A=2^2+4^4+6^2+...98^2\)
\(\frac{1}{4}A=1^2+2^2+3^2+...+49^2\)
\(\frac{1}{4}A=\frac{49.50.\left(2.49+1\right)}{6}\)
\(\frac{1}{4}A=40425\)
\(A=40425.4=161700\)
=>\(2^2+4^2+6^2+...+98^2=161700\)
`a)-2/3-2/6+2/12+2/24+2/48+2/96+2/192`
`=-4/6-2/6+1/6+1/12+1/24+1/48+1/96`
`=-5/6+1/12+1/24+1/48+1/96`
`=-10/12+1/12+1/24+1/48+1/96`
`=-9/12+1/24+1/48+1/96`
`=-18/24+1/24+1/48+1/96`
`=-17/24+1/48+1/96`
`=-34/48+1/48+1/96`
`=-33/48+1/96`
`=-66/96+1/96=-65/96`
Đặt \(A=\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{98}+\dfrac{2}{192}\)
\(2A=\dfrac{4}{3}+\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{98}+\dfrac{2}{192}\)
\(2A-A=\left(\dfrac{4}{3}+\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{98}+\dfrac{2}{192}\right)-\left(\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{98}+\dfrac{2}{192}\right)\)
\(A=\dfrac{4}{3}-\dfrac{2}{192}\)
\(A=\dfrac{127}{96}\)
Vậy \(A=\dfrac{127}{96}\)
Mình hơn nhầm ở chỗ 98 viết lại thành 96. thông cảm nha mình làm lại cho:
Đặt \(A=\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{96}+\dfrac{2}{192}\)
\(2A=\dfrac{4}{3}+\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{96}+\dfrac{2}{192}\)
\(2A-A=\left(\dfrac{4}{3}+\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{96}+\dfrac{2}{192}\right)-\left(\dfrac{2}{3}+\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{24}+\dfrac{2}{48}+\dfrac{2}{96}+\dfrac{2}{192}\right)\)
\(A=\dfrac{4}{3}-\dfrac{2}{192}\)
\(A=\dfrac{127}{96}\)
Vậy \(A=\dfrac{127}{96}\)
Đặt tổng trên = A
\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\)
\(A.2=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\)
\(A.2-A=\left(\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\right)-\left(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\right)\)
\(A=\frac{4}{3}-\frac{2}{192}\)
\(A=\frac{127}{96}\)
\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\)
\(2A=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\)
\(2A-A=\frac{4}{3}-\frac{2}{192}\)
\(A=\frac{4}{3}-\frac{2}{192}=\frac{127}{96}\)