Câu hỏi của Ảo ảnh tam kiếm

Question

Tính A= (16^3*3^10+120*6^9) / 4^6*3^12+6^11

Giải nhanh hộ mik với

Lung Thị Linh · Accepted Answer

$A=\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}$

$A=\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}$

$A=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{11}.3^{11}}$
$A=\frac{2^{11}.3^{10}\left(2+2.5\right)}{2^{11}.3^{10}\left(2.3^2+3\right)}$

$A=\frac{2+10}{14}$

$A=\frac{6}{7}$

Câu trả lời:

$A=\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}$

$A=\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{11}}$

$A=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{11}.3^{11}}$
$A=\frac{2^{11}.3^{10}\left(2+2.5\right)}{2^{11}.3^{10}\left(2.3^2+3\right)}$

$A=\frac{2+10}{14}$

$A=\frac{6}{7}$