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5^6+5^7+5^8
=5^6.(1+5+5^2)
=5^6.31 chia hết cho 31
7^6+7^5-7^4
=7^4.(7^2+7-1)
=7^4.55 chia hết cho 11
BÀI 2:
a) \(5^6+5^7+5^8=5^6\left(1+5+5^2\right)=5^6.31\) \(⋮\)\(31\)
b) \(7^6+7^5-7^4=7^4.\left(7^2+7-1\right)=7^4.55\)\(⋮\)\(11\)
c) \(2^3+2^4+2^5=2^3.\left(1+2+2^2\right)=2^3.7\)\(⋮\)\(7\)
d) mk chỉnh đề
\(1+2+2^2+2^3+...+2^{59}\)
\(=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{58}+2^{59}\right)\)
\(=\left(1+2\right)+2^2\left(1+2\right)+...+2^{58}\left(1+2\right)\)
\(=\left(1+2\right)\left(1+2^2+...+2^{58}\right)\)
\(=3\left(1+2^2+...+2^{58}\right)\)\(⋮\)\(3\)
a) 8x+2x = 25.22
8x+2x = 25. 4
8x+2x = 100
( 8 + 2) . x = 100
10 . x =100
x =100 :10
x =10
a)\(2^x.4=128\Leftrightarrow2^x=32\Leftrightarrow2^x=2^5\Rightarrow x=5\)
b)\(\left(2x+1\right)=125\Leftrightarrow2x=126\Leftrightarrow x=13\)
c)\(x^{15}=x\Leftrightarrow\orbr{\begin{cases}x=\pm1\\x=0\end{cases}}\)
d) \(\left(x-5\right)^4=\left(x-5\right)^5\Leftrightarrow\orbr{\begin{cases}x-5=1\\x-5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=5\end{cases}}\)
a,
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
b,
2x = 124
x = 62
c,
\(x^{15}-x=0\)
\(x\left(x^{14}-1\right)=0\)
\(\orbr{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)
\(\orbr{\begin{cases}x=0\\x^{14}=1\end{cases}}\)
\(\orbr{\begin{cases}x=0\\x=\pm1\end{cases}}\)
d,
\(0=\left(x-5\right)^5-\left(x-5\right)^4\)
\(\left(x-5\right)^4\left(x-5-1\right)=0\)
\(\orbr{\begin{cases}\left(x-5\right)^4=0\\x-6=0\end{cases}}\)
\(\orbr{\begin{cases}x=5\\x=6\end{cases}}\)
\(\Leftrightarrow5^{2x}:5^3=5^2.3+2.5^2\)
\(\Leftrightarrow5^{2x}.5^3=5^2.5\)
\(\Leftrightarrow5^{2x}=5^2.5.5^3\)
\(\Leftrightarrow5^{2x}=5^6\Rightarrow2x=6\Rightarrow x=3\)