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\(A=1+4+4^2+4^3+4^4+4^5+4^6+4^7+4^8\)
\(A=1+4^{1+2+3+4+5+6+7+8}\)
\(A=1+4^{36}\)
khó quá cậu ơi
a/ 440 + 2 [ 125 - x ] = 546
==> 2 [ 125 - x ] = 546 - 440
==> 2 [ 125 - x ] 106
==> 125 - x = 106 : 2
==> 125 - x = 53 ==> x = 125 - 53 =72
b/ 7x - 33 = 27 : 24
==> 7x - 27 = 27-4 = 23 = 8
==> 7x = 8+ 27
==> 7x = 35 ==> x = 35 : 7 = 5
c/ [ 12x - 43 ] . 83 = 4 . 84
==> [ 12x - 26 ] . 29 = 22 . 212
==> [ 12x - 26 ] . 29 = 214
==> [ 12x - 26 ] = 214 : 29 = 25
==>. 12x = 25 + 26 = 96
==> x = 96 : 12 = 8
d/ 123 - 5. [ x + 4 ] = 38
==> 5. [ x + 4 ] = 123 - 38
==> 5. [ x + 4 ] = 85
==> x + 4 = 85 : 5
==> x + 4 = 17
==> x = 17 - 4 = 13
e/ [ 2600 + 6400 ] - 3.x = 1200
==> 9000 - 3x = 1200
==> 3x = 9000 -1200 = 7800
==> x = 7800 : 3 = 2600
f/ x2 - 72 : 36 = 23
==> x2 - 2 = 23
==> x2 = 23 + 2
==>x2 = 25
==> x2 = 52
==> x = 5
a)A=5+52+53+...+58
A= (5+52)+(53+54) + ... + (57+58)
A= 5( 1+5) + 52(5+52)+... + 56(5+52)
A= 30 + 52 . 30 + ... +56.30
A = 30 ( 1 + 52+...+56) chia hết cho 30
=> A chia hết cho 30
b)B=3+33+35+37+...+329
B = (3 + 33 + 35) + (37+39+311) + ... + ( 327+328+329)
B = 273 + 36 (3 + 33 + 35) + ... + 326 (3 + 33 + 35)
B = 273 + 36.273 + ... + 326.273
B = 273 ( 1 + 36+...326) chia hết cho 273
=> B chia hết cho 273
Mình nghĩ sửa 3 thành 1 sẽ hợp lí hơn
a)\(S=1+3^2+3^4+...+3^{2002}\)
=>\(3^2.S=3^2+3^4+3^6+...+3^{2004}\)
=>\(9S-S=\left(3^2+3^4+3^6+...+3^{2004}\right)-\left(1+3^2+3^4+...+3^{2002}\right)\)
=>\(8S=3^{2004}-1\)
=>\(S=\frac{3^{2004}-1}{8}\)
b)\(S=1+3^2+3^4+...+3^{2002}\)
=>\(S=\left(1+3^2+3^4\right)+...+\left(3^{1998}+3^{2000}+3^{2002}\right)\)
=>\(S=91+...+3^{1998}\left(1+3^2+3^4\right)\)
=>\(S=91+...+3^{1998}.91\)
=>\(S=91\left(1+...+3^{1998}\right)\)
=>\(S=7.13.\left(1+...+3^{1998}\right)\) chia hết cho 7 (đpcm)
1) 6x+x=28 => 7x=28 => x= 28:7=4.
2) \(5x+x=39-3^{11}:3^9=>6x=39-3^2=>6x=39-9=>6x=30=>x=30:6=5\)
3) \(7x-x=5^{21}:5^{19}+3.2^2-7^0.7\)
\(6x=5^2+3.4-1.7=>6x=25+12-7=>6x=30=>x=30:6=5.\)
4)\(7x-2x=6^{17}:6^{15}+44:11=>5x=6^2+4=>5x=36+4=>5x=40=>x=40:5=8.\)
7x-x=521:519+3.22-70
=> 6x = 5^2 + 12 -1
=> 6x = 36
=> x = 36/6 = 6
Kết quả 6
Học tốt
5^6+5^7+5^8
=5^6.(1+5+5^2)
=5^6.31 chia hết cho 31
7^6+7^5-7^4
=7^4.(7^2+7-1)
=7^4.55 chia hết cho 11
BÀI 2:
a) \(5^6+5^7+5^8=5^6\left(1+5+5^2\right)=5^6.31\) \(⋮\)\(31\)
b) \(7^6+7^5-7^4=7^4.\left(7^2+7-1\right)=7^4.55\)\(⋮\)\(11\)
c) \(2^3+2^4+2^5=2^3.\left(1+2+2^2\right)=2^3.7\)\(⋮\)\(7\)
d) mk chỉnh đề
\(1+2+2^2+2^3+...+2^{59}\)
\(=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{58}+2^{59}\right)\)
\(=\left(1+2\right)+2^2\left(1+2\right)+...+2^{58}\left(1+2\right)\)
\(=\left(1+2\right)\left(1+2^2+...+2^{58}\right)\)
\(=3\left(1+2^2+...+2^{58}\right)\)\(⋮\)\(3\)